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2 years ago

Which of the following points lies in Quadrant II?

Mathematics

2 answers:

RUDIKE [14]2 years ago

6 0

The answer is d. (-3,8.)

statuscvo [17]2 years ago

6 0

The answer is (-3,8)

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Slope intercept form 3x-10y=-6

Anuta_ua [19.1K]

Answer:

y=3/10x+0.6

Step-by-step explanation:

3x-10y=-6

-3x -3x

-10y=-3x-6

Divide -10 from everything.

y=3/10x+0.6

4 0

3 years ago

The ratio of Zoey's money to Andrew's money is 4:5. If Zoey has $28, how much do they have altogether?

quester [9]

Answer: 1. 63; 2. 84; 3. 104 4. 1:2

Step-by-step explanation: Since Zoey has $28, and the ratio is 4:5, we can multiply the ratio by 7 on both sides so that it is 28:35, giving $35 for andrew, and this $28+$35=$63. Since the ratio of red to white marbles has a sum of 10, but there are 120, we multiply the ratio by 120/10=12, to make the ratio applicable to the scenario, so 7 times 12 = 84 red marbles. Same way for the theater question, 195/15=13, so 8 times 13= 104, and so 104 people are boys. For the last question you can simply divide both sides by 5 (or think of it as a fraction, 5/10=1/2).

6 0

2 years ago

6+(square root)44/2 please help

Temka [501]

U can try desmos calculator helps me with all those types of questions!!

6 0

2 years ago

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago

3(7v-5)-v(10v-9) how do is solve this problem

Alika [10]

3(7v-5)-v(10v-9) = 21v - 15 -10v² + 9v = - 10v² + 30v - 15

8 0

2 years ago