Answer:
The perimeter of the square after dilation will be 242 mm
Step-by-step explanation:

Answer:
Step-by-step explanation:
13). Area of a square = (Side)²
= (BC)²
Since, diagonals of a square bisect each other at 90°,
ΔBOC is a right triangle.
By applying Pythagoras theorem in the given triangle,
BC² = OB² + OC²
BC² = 2(OB)²
BC² = 2(7√2)²
BC = 
Area of square ABCD = (BC)²
= (√196)²
= 196 units²
14). Measure of interior angles of the regular hexagon = 120°
Area of the regular hexagon = 
From the given picture,
m∠BAC = m∠ABC = m∠ACB = 60°
Therefore, ΔABC is an isosceles triangle.
And all sides of this triangle will be equal in measure.
AB = AC = BC = 9 units
Area of the given regular hexagon = 
= 210.44 square units
≈ 210.4 square units
Answer:
Step-by-step explanation:
Here the region between two curves is rotated about a vertical line.
The functions are
![y = sin^2x, \\y = sin^4x, \\x in [0,[pi]/2].](https://tex.z-dn.net/?f=y%20%3D%20sin%5E2x%2C%20%5C%5Cy%20%3D%20sin%5E4x%2C%20%5C%5Cx%20in%20%5B0%2C%5Bpi%5D%2F2%5D.)
Intersecting points are x=0 and x =pi/2
Since rotated about x = pi/2 we get
using cylindrical shell method
Volume = 
From wolfram alpha we find that
Volume= 
Answer:
(x + 3) ( x - 6)
Step-by-step explanation:
x² - 3x - 18
x² - 6x + 3x - 18
x(x - 6) + 3(x - 6)
(x + 3) ( x - 6)
UW; Converse of the Isosceles Triangle Theorem
This is the answer because angles T and W are congruent. Meaning that they make an isosceles triangle. The two sides connecting to those angles should be congruent. Therefore UT and UW are congruent.