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WINSTONCH [101]
4 years ago
10

Determine the type and number of solutions of x^2 + 10x − 25 = 0. A two real solutions B one real solution C two imaginary solut

ions
Mathematics
1 answer:
klemol [59]4 years ago
4 0

Answer:

two real solution

Step-by-step explanation:

x^2 + 10x − 25 = 0

we can solve this by finding out the value of x

lets assume the equation is   a\times x^{2}+b\times x+c=0

x=-b\pm \sqrt{(b^{2}-4ac)}\div 2a

x=-10\pm\sqrt{100+4*25}\div2

x=-5\pm5\sqrt2

then we get both real value of x

so two real solution

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3 years ago
Find θ if θ is between 0° and 90°. round your answer to the nearest tenth of a degree. csc θ = 1.6981
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3 years ago
The table shows the heights of 40 students in a class.
Studentka2010 [4]

Answer:

Step-by-step explanation:

Hello!

a)

The given information is displayed in a frequency table, since the variable of interest "height of a student" is a continuous quantitative variable the possible values of height are arranged in class intervals.

To calculate the mean for data organized in this type of table you have to use the following formula:

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fi represents the observed frequency for each class

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<u>Class marks:</u>

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Note: all class marks are always within the bonds of its class interval, and their difference is equal to the amplitude of the intervals.

n= 7 + 8 + 13 + 9 + 3= 40

X[bar]= (∑x'fi)/n= [(x₁'*f₁)+(x₂'*f₂)+(x₃'*f₃)+(x₄'*f₄)+(x₅'*f₅)]/n) = [(122*7)+(126*8)+(130*13)+(134*9)+(138*3)]/40= 129.3

The estimated average height is 129.3cm

b)

This average value is estimated because it wasn't calculated using the exact data measured from the 40 students.

The measurements are arranged in class intervals, so you know, for example, that 7 of the students measured sized between 120 and 124 cm (and so on with the rest of the intervals), but you do not know what values those measurements and thus estimated a  mean value within the interval to calculate the mean of the sample.

I hope this helps!

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4 years ago
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Step-by-step explanation:

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3 years ago
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