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3 years ago

If f is the function given by f(x)= integral from (4 to 2x) of sqrt(t^2-t)dt then f'(2) =?

2 answers:

5 0

The question ask to calculate the function f'(2) in the F is the function given by f(x) = integral from (4 to 2x) of sqrt(t^2-t), base on that, the possible answer would be that the f(2) is 4 sqrt 3. I hope you are satisfied with my answer and feel free to ask for more if you have questions

sammy [17]3 years ago

3 0

Hello,

$f(x)= \int\limits^{2x}_4 {\sqrt{t^2-t} \, dt \\

 \dfrac{df(x)}{dx} = \dfrac{df(x)}{d(2x)} * \dfrac{d(2x)}{dx} =2* \sqrt{(2x)^2-2x} \\

f'(2)=2 * \sqrt{4^2-4} =2* \sqrt{12} =4 \sqrt{3}$

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2 years ago

What the answer guys?

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3 years ago

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4 0

3 years ago

(2y-at)(y+2at) find the product

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6 0

3 years ago

Read 2 more answers

How does 1/8 divided by 1/4 equal 1/2?

photoshop1234 [79]

When you divide a fraction by a fraction, you're really just multiplying by a reciprocal. A reciprocal is the fraction flipped around.
So, 1/8 ÷ 1/4 is the same thing as 1/8 x 4/1
Now, you just multiply. 1 times 4 is 4. 8 times 1 is 8.
1/8 x 4/1=4/8
4/8 simplified is 1/2
So that is how 1/8÷1/4=1/2

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3 years ago