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Free_Kalibri [48]
3 years ago
5

We know that angle 1 is congruent to angle 3 and that line a is parallel to line b because they are given. We see that _________

_ by the alternate exterior angles theorem. Therefore, angle 2 is congruent to angle 3 by the transitive property. So, we can conclude that lines e and f are parallel by the converse alternate exterior angles theorem.
Which information is missing in the paragraph proof?

∠2 ≅ ∠4
∠1 ≅ ∠2
∠2 ≅ ∠3
∠1 ≅ ∠4
Mathematics
2 answers:
Virty [35]3 years ago
5 0

Answer:

  ∠1 ≅ ∠2

Step-by-step explanation:

The transitive property says that if ∠1 ≅ ∠3 and ∠1 ≅ ∠2, then ∠2 ≅ ∠3. The missing part of this statement in the paragraph is ∠1 ≅ ∠2.

Hoochie [10]3 years ago
4 0

Answer:

\angle 1\cong \angle 2

Step-by-step explanation:

We have to find the missing statement in the given proof.

Angle 1 is congruent to angle 3

Given

Line a is parallel to line b

Given

\angle 1\cong \angle 2

By using alternate exterior angles theorem.

\angle 2\cong \angle 3

Therefore, \angle 2\cong \angle 3

By the transitive property of congruence.

So, we can conclude that lines e and f are parallel by the converse alternate exterior angles theorem.

Answer:\angle 1\cong \angle 2

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tatyana61 [14]

Answer:

1.7 × 10⁻⁴

Step-by-step explanation:

The question relates to a two sample z-test for the comparison between the means of the two samples  

The null hypothesis is H₀:  μ₁ ≤ μ₂

The alternative hypothesis is Hₐ: μ₁ > μ₂

z=\dfrac{(\bar{x}_1-\bar{x}_2)-(\mu_{1}-\mu _{2} )}{\sqrt{\dfrac{\sigma_{1}^{2} }{n_{1}}-\dfrac{\sigma _{2}^{2}}{n_{2}}}}

Where;

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For n₁ = n₂ = 23, we have;

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Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983

Therefore;

The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.

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