Ask question

Ask question

All categories

Free_Kalibri [48]

3 years ago

5

We know that angle 1 is congruent to angle 3 and that line a is parallel to line b because they are given. We see that _________

_ by the alternate exterior angles theorem. Therefore, angle 2 is congruent to angle 3 by the transitive property. So, we can conclude that lines e and f are parallel by the converse alternate exterior angles theorem.
Which information is missing in the paragraph proof?

∠2 ≅ ∠4
∠1 ≅ ∠2
∠2 ≅ ∠3
∠1 ≅ ∠4

2 answers:

Virty [35]3 years ago

5 0

Answer:

∠1 ≅ ∠2

Step-by-step explanation:

The transitive property says that if ∠1 ≅ ∠3 and ∠1 ≅ ∠2, then ∠2 ≅ ∠3. The missing part of this statement in the paragraph is ∠1 ≅ ∠2.

Hoochie [10]3 years ago

4 0

Answer:

$\angle 1\cong \angle 2$

Step-by-step explanation:

We have to find the missing statement in the given proof.

Angle 1 is congruent to angle 3

Given

Line a is parallel to line b

Given

$\angle 1\cong \angle 2$

By using alternate exterior angles theorem.

$\angle 2\cong \angle 3$

Therefore, $\angle 2\cong \angle 3$

By the transitive property of congruence.

So, we can conclude that lines e and f are parallel by the converse alternate exterior angles theorem.

Answer: $\angle 1\cong \angle 2$

You might be interested in

What is the slope of a line perpendicular to the line containing the points (4,-7) and (-5,-1)? Express your answer as a common

just olya [345]

Answer:

3/2

Step-by-step explanation:

Slope 1 = (-1+7)/(-5-4) = 6/(-9) = -2/3

Slope 2 perpendicular to Slope 1 :

-1 ÷ -⅔ = 3/2

6 0

3 years ago

The population of Wakanda is 5231281. Wakanda is about 70323 square miles. What is the population density of Wakanda? Round your

Mila [183]

5.231.281 : 70.323 = 74,3 people per square mile
or 74 people per square mile

7 0

3 years ago

LekaFEV [45]

Answer:

7x^(2)-3x+8

Step-by-step explanation:

(5x^(2) - 3x - 2) - (-2x^(2) - +10)

(5x^(2))- (-2x^(2))=7x^(2)

(- 2)-(+10)=+8

7x^(2)-3x+8

6 0

3 years ago

For waht values of x do the vectors -1,0,-1), (2,1,2), (1,1, x) form a basis for R3?

DaniilM [7]

<h2>Answer:</h2>

The values of x for which the given vectors are basis for R³ is:

$x\neq 1$

<h2>Step-by-step explanation:</h2>

We know that for a set of vectors are linearly independent if the matrix formed by these set of vectors is non-singular i.e. the determinant of the matrix formed by these vectors is non-zero.

We are given three vectors as:

(-1,0,-1), (2,1,2), (1,1, x)

The matrix formed by these vectors is:

$\left[\begin{array}{ccc}-1&2&1\\0&1&1\\-1&2&x\end{array}\right]$

Now, the determinant of this matrix is:

$\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-1(x-2)-2(1)+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+2-2+1\\\\\\\begin{vmatrix}-1 &2 & 1\\ 0& 1 & 1\\ -1 & 2 & x\end{vmatrix}=-x+1$

Hence,

$-x+1\neq 0\\\\\\i.e.\\\\\\x\neq 1$

4 0

3 years ago

What are the coordinates of P' if P (-5,-4) undergoes a dilation, centered at the origin, with a scale factor of K=2?

Margaret [11]

Answer:

$P' = (-10,-8)$

Step-by-step explanation:

Given

$P = (-5,-4)$

$k =2$

Required

Determine the image P'

P' is calculated by multiplying P and k.

i.e.

$P' = P * k$

This gives:

$P' = (-5,-4) * 2$

$P' = (-5* 2,-4* 2)$

$P' = (-10,-8)$

<em>Hence, the image P' after dilating P is (-10,-8)</em>

7 0

3 years ago