Answer:The value of the bulldozer after 3 years is $121950
Step-by-step explanation:
We would apply the straight line depreciation method. In this method, the value of the asset(bulldozer) is reduced linearly over its useful life until it reaches its salvage value. The formula is expressed as
Annual depreciation expense =
(Cost of the asset - salvage value)/useful life of the asset.
From the given information,
Useful life = 23 years
Salvage value of the bulldozer = $14950
Cost of the new bulldozer is $138000
Therefore
Annual depreciation = (138000 - 14950)/ 23 = $5350
The value of the bulldozer at any point would be V. Therefore
5350 = (138000 - V)/ t
5350t = 138000 - V
V = 138000 - 5350t
The value of the bulldozer after 3 years would be
V = 138000 - 5350×3 = $121950
Answer:Solution:
Let starting map of youth center has Dimension (Preimage)
1 unit of y= k units
1 unit of x = t units
The new map of youth center which is 3 times larger than original(Image)
1 unit of y= 3 k units
1 unit of x = 3 t units
Image = 3 × Pre- image
The image is larger than Pre- image.
So, Scale of the new map = 3 × The original dimension of map.
Step-by-step explanation:
Since it would be 60% of the original price which is 500 it would have be $300
The number of electrons in a neutral atom is equal to the number of protons. The mass number of the atom (M) is equal to the sum of the number of protons and neutrons in the nucleus. The number of neutrons is equal to the difference between the mass number of the atom (M) and the atomic number. it could be A
