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Aleksandr [31]
2 years ago
14

Plz help me plz someone plz help me plz

Mathematics
1 answer:
Licemer1 [7]2 years ago
6 0

To solve, start by counting how many units is B to A <em>or </em>A to B? 7. Now mirror this across. ( or reflect. )

When mirroring something, it will turn out to the same. So, it is respectively, 7.

So the answer is 7.

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X – 6y - 9 = 0 x = 8y + 6 What is a resulting equation?
serious [3.7K]

Answer:

-2y + 3 = 0

Step-by-step explanation:

x - 6y - 9 = 0

-6y - 9 = -x                          subtract x from both sides

6y + 9 = x                            divide both sides by -1

x = 8y + 6

6y + 9 = 8y + 6                    replace x with 6y + 9

-2y + 9 = 6                           subtract 8y from both sides

-2y + 3 = 0                            subtract 6 from both sides

3 0
2 years ago
Solve for x. PLEASE HELP ASAP WILL GIVE BRAINLIEST ANSWER
murzikaleks [220]

Answer:

x = 2.6  

Step-by-step explanation:

To find x, you need to find how many times you need to multiply 25 to get 65. Using reverse operations will make this easier. 65 / 25 = 2.6. We can check this by multiplying 25 by 2.6, and we get 65.

3 0
3 years ago
How can I find the volume of L shape blocks
Anvisha [2.4K]
The formula for volume is length multiplied by width multiplied by height
I hope this helps sorry if it doesn't :)
8 0
3 years ago
1 point
SpyIntel [72]

Answer:

20

Step-by-step explanation:

IF you are asking why it is because 50-32=18 than you do 18/.90 which equals 20 so there you go thanks make brainliest

3 0
3 years ago
The dashed-line triangle is a dilation image of the solid-lined triangle.
Gre4nikov [31]
Refer to the edited figure.

Triangles ABC and A'B'C' are similar because of AAA.
Also,
\frac{AB}{A'B'}= \frac{15}{5}=3 \\\\  \frac{AC}{A'C'}= \frac{12}{4}=3

Therefore
ΔA'B'C' is 1/3 the size of ΔABC.
This means that the scale factor from ΔABC to ΔA'B'C' is a 3-factor reduction.

Answer:   reduction; one-third.
The dilation is a reduction.
The scale factor of the dilation is one-third.

8 0
3 years ago
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