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3 years ago

Someone pls help me . I will mark you brainliest !! thank you sm .

Mathematics

1 answer:

Sidana [21]3 years ago

3 0

Answer:

first one is 27.89, the second is 20.

Step-by-step explanation:

1. So the 340 dollars is determined by 9.50 multiplied by the amount of hours you show up (which we will call x), plus the 75 dollars.

Your equation will be set up like this : 9.50x +75 = 340

So, to get x, we must isolate it. so subtract 75 from both sides

9.50x +75 -75 = 340 -75 9.50x = 265

Now, since we know that 9.50 multiplied by x equals 265, to isolate and find out x (the hours worked during the pay period), we divide both sides by 9.50

9.50x/9.50 = 265/9.50 so, x = 27.89473684, but based off of the answers there, you would just round to x = 27. 89 hours worked.

2. So now the 120 chips are determined by 6 chips multiplied by the minutes, since 6 chips are eaten every minute, with the minutes represented as x, like this: 6x = 120

So this time, you don't subtract or add anything, you would just divide by 6 to isolate x.

6x/6 = 120/6 so, x = 20 minutes.

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Given that x is an integer such that <img src="https://tex.z-dn.net/?f=%5Cx%5Csqrt%7Bx%7D-5x-9%5Csqrt%7Bx%7D%3D35%5B" id="TexFor

Talja [164]

I have done this several times and do not find that x is an integer. I get an imaginary number. Crazy as it seems, here's what I got all 3 times I did this: $-\frac{286}{50} +/- \frac{16i \sqrt{159} }{50}$ . That is definitely NOT an integer!

7 0

3 years ago

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The weights of soy patties sold by Veggie Burgers Delight are normally distributed. A random sample of 15 patties yields a mean

Elden [556K]

Answer:

$t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549$

Step-by-step explanation:

Data given and notation

$\bar X=3.8$ represent the sample mean

$s=0.5$ represent the sample standard deviation for the sample

$n=15$ sample size

$\mu_o =4$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean weight is less than 4 ounces, the system of hypothesis would be:

Null hypothesis: $\mu \geq 68$

Alternative hypothesis: $\mu < 4$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{3.8-4}{\frac{0.5}{\sqrt{15}}}=-1.549$

3 0

3 years ago

Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50. Jason went into the same movi

ruslelena [56]

The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

Solution:

Let d" be the price of 1 drink

Let "p" be the price of 1 pretzel

Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50

Therefore, we can frame a equation as,

3 x price of 1 drink + 10 x price of 1 pretzel = 54.50

$3 \times d + 10 \times p = 54.50$

3d + 10p = 54.5 ---------- eqn 1

Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25

9 x price of 1 drink + 5 x price of 1 pretzel = 57.25

$9 \times d + 5 \times p = 57.25$

9d + 5p = 57.25 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

9d + 30p = 163.5 ----- eqn 3

Subtract eqn 2 from eqn 3

9d + 30p = 163.5

9d + 5p = 57.25

( - ) -----------------------

25p = 106.25

p = 4.25

Substitute p = 4.25 in eqn 1

3d + 10(4.25) = 54.5

3d + 42.5 = 54.5

3d = 54.5 - 42.5

3d = 12

d = 4

Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

4 0

3 years ago

35 POINTS!!! PLEASE HELP !!!!!!!!!!!!!!

lyudmila [28]

Answer:

The function is increasing from x = 0 to x = 1.

Step-by-step explanation:

A function is increasing when the y-value increases as the x-value increases.

A function is decreasing when the y-value decreases as the x-value increases.

From x = -2 to x = -1 the function is decreasing as the y-value decreases as the x-value increases:

x-value -2 to -1 → increase
y-value 2 to 0 → decrease

From x = -1 to x = 0 the function is increasing as the y-value increases as the x-value increase:

x-value -1 to 0 → increase
y-value 0 to 2 → increase

From x = 0 to x = 1 the function is increasing as the y-value increases as the x-value increase:

x-value 0 to 1 → increase
y-value 2 to 8 → increase

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2 years ago

Find the commutative property of multiplication

exis [7]

Answer:

they are all true they are just expressed different

Step-by-step explanation:

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3 years ago

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