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3 years ago

Find the commutative property of multiplication

Mathematics

2 answers:

exis [7]3 years ago

8 0

Answer:

they are all true they are just expressed different

Step-by-step explanation:

Pachacha [2.7K]3 years ago

6 0

The answer is 2 because a+b=b+a

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What is 1/10 Of 200. I don't now help plZ

inna [77]

It is 20 because 20/200=10/100=1/10

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3 years ago

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The Skubic family and the Shaw family went on a safari tour in which they drove their own vehicles through the park to view the

VMariaS [17]

Answer:

$12.75

Step-by-step explanation:

Skubic Family-

22.75 = 5.25 + 7x

17.5 = 7x

2.5 = x

Therefore the cost for each person is equal to $2.5

Shaw Family-

2.5(3) + 5.25

7.5 + 5.25 = $12.75

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3 years ago

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Solve the equation 2cosA = 3tanA

zavuch27 [327]

$\bf sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\\\
tan(\theta)=\cfrac{sin(\theta)}{cos(\theta)}\\\\
-----------------------------\\\\

2cos(A)=3tan(A)\implies 2cos(A)=3\cfrac{sin(A)}{cos(A)}
\\\\\\
2cos^2(A)=3sin(A)\implies 2[1-sin^2(A)]=3sin(A)
\\\\\\
2-2sin^2(A)=3sin(A)\implies 2sin^2(A)+3sin(A)-2$

$\bf \\\\\\
0=[2sin(A)-1][sin(A)+2]\implies 
\begin{cases}
0=2sin(A)-1\\
1=2sin(A)\\
\frac{1}{2}=sin(A)\\\\
sin^{-1}\left( \frac{1}{2} \right)=\measuredangle A\\\\
\frac{\pi }{6},\frac{5\pi }{6}\\
----------\\
0=sin(A)+2\\
-2=sin(A)
\end{cases}$

now, as far as the second case....well, sine of anything is within the range of -1 or 1, so -1 < sin(A) < 1

now, we have -2 = sin(A), which simply is out of range for a valid sine, so there's no angle with such sine

so, only the first case are the valid angles for A

8 0

3 years ago

51 decreased by twice Jose's height <br>use the variable j to represent Jose's height.<br>

makkiz [27]

Step-by-step explanation:

51 - 2j

maybe something is missing here, but that is the representation of what you wrote.

3 0

3 years ago

You currently have a 67% in class. You have 2 more assignments a quiz which is 10% and a project worth 45%. Lets say I get a 100

finlep [7]

Answer:

82% I think I hope this helped

6 0

3 years ago