Question

Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50. Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25. Determine the price of each drink and the price of each pretzel.

Answer 1

The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

Solution:

Let d" be the price of 1 drink

Let "p" be the price of 1 pretzel

Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50

Therefore, we can frame a equation as,

3 x price of 1 drink + 10 x price of 1 pretzel = 54.50

$3 \times d + 10 \times p = 54.50$

3d + 10p = 54.5 ---------- eqn 1

Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25

9 x price of 1 drink + 5 x price of 1 pretzel = 57.25

$9 \times d + 5 \times p = 57.25$

9d + 5p = 57.25 ---------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 3

9d + 30p = 163.5 ----- eqn 3

Subtract eqn 2 from eqn 3

9d + 30p = 163.5

9d + 5p = 57.25

( - ) -----------------------

25p = 106.25

p = 4.25

Substitute p = 4.25 in eqn 1

3d + 10(4.25) = 54.5

3d + 42.5 = 54.5

3d = 54.5 - 42.5

3d = 12

d = 4

Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25