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2 years ago

What’s the surface area of a triangular pyramid

1 answer:

Nutka1998 [239]2 years ago

8 0

To find the surface area of a regular triangular pyramid, we use the formula SA = A + (3/2)bh, where A = the area of the pyramid's base, b = the base of one of the faces, and h = height of one of the faces.

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Consider a binomial experiment with n=2 and p=0.6

nalin [4]

Answer:

x=?

Step-by-step explanation:

12xn=20xp

8 0

2 years ago

Simplify This Radical Expression

balandron [24]

Answer:

The answer is: -0.5198

Step-by-step explanation:

CUBERT(8) – CUBERT(16) is the cube root of 8 - cube root of 16:

CubeRT(8) - CubeRT(16) =

2 - 2.5198 = -0.5198

Hope this helps! Have an Awesome day!! :-)

5 0

2 years ago

-4(2x + 4) > 8x + 64

romanna [79]

Hello there I hope you are having a great day :)

Your Question, -4(2x + 4) > 8x + 64 Solve for X

1) Expand -8x-16>8x+64

2) Add 16 to both sides -8x-16+16>8x+64+16

3) Simplify -8x>8x+80

4) Subtract 8x from both sides -8x-8x>8x+80-8x

5) Simplify -16x>80

6) Multiply both sides -1 (Reverse the inequality) (-16x) (-1) >80 (-1)

7) Simplify 16x<-80

8) divide both sides by 16 16x/16 < -80/16

9) Simplify x < -5

This should be your answer x < -5

Hopefully that helps you :)

5 0

1 year ago

Read 2 more answers

5\times 100+4\times 10+6\times 1+2\times \left(\frac{1}{10}\right)+8\times \left(\frac{1}{1000}\right)5×100+4×10+6×1+2×(

adell [148]

Answer:could you make it more clear

Step-by-step explanation:

I don’t understand

8 0

2 years ago

Which polynomial correctly combines the like terms and puts the given polynomial in standard form? -5x^3y^3+8x^4y^2-xy^5-2x^2y^4

victus00 [196]

Given:

The polynomial is:

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

To find:

The simplified form of the given polynomial in standard form.

Solution:

We have,

$-5x^3y^3+8x^4y^2-xy^5-2x^2y^4+8x^6+3x^2y^4-6xy^5$

Combining the like terms, we get

$=-5x^3y^3+8x^4y^2+(-2x^2y^4+3x^2y^4)+8x^6+(-xy^5-6xy^5)$

$=-5x^3y^3+8x^4y^2+x^2y^4+8x^6-7xy^5$

Now, rewrite this polynomial in standard form.

$=8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$

Therefore, the required polynomial in standard form is $8x^6+8x^4y^2-5x^3y^3+x^2y^4-7xy^5$ .

8 0

2 years ago