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3 years ago

Consider the inequality X > - 2.5 Determine whether each value of X makes this inequality true Select ALL that apply.

Mathematics

2 answers:

Leno4ka [110]3 years ago

6 0

Answer:

The correct answers are: 0.5, 3, and 10.

Basically, all numbers that are greater than -2.5 can make this inequality true.

Let me know if this helps!

grigory [225]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

Write 6 1 2 as an improper fraction.

kompoz [17]

Answer:

13/2

Step-by-step explanation:

you do 6*2=12+1=13 which gives ya 13/2

you keep the denominator

3 0

4 years ago

Write a few sentences explaining how to determine whether a relation shown in a table or a graph is a function.

ohaa [14]

Answer:

y=f(x)

y=5x

y=3x

are examples of function

Step-by-step explanation:

definition of a function

if there is one to one relation between a relation

then it is defined as a function

for example

y=5x is a function

because when we put some value of x it gives back only one value of y as output.

y=±5x is not a function because one value of x gives two values(positive and negative) values of y hence not a function.

8 0

3 years ago

2 divided by what times what equals 7

g100num [7]

Answer:

Step-by-step explanation:

I answer for what I understand, the question is not clear.

2 divided by what times what equals 7

2 : x = 7

x = -2/-7

x = 2/7

-------------

check

2 : 2/7 = 7

2 * 7/2 = 7

7 = 7

the answer is good

5 0

2 years ago

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

bulgar [2K]

Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80% = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

$\large P(20;k)=\binom{20}{k}(0.2)^k(0.8)^{20-k}$

We are looking for

P(0;20)+P(0;1)+P(0;2) =

$\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=$

0.0115292150460685 + 0.0576460752303424 + 0.136909428672063 = 0.206084718948474≅ 0.2061 or 20.61%

Here we want P(20;4)

$\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%$

Here we need

$\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)$

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

$\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%$

For a binomial distribution the expectance of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = 4 withdrawals.

3 0

3 years ago

Helena, Violet, and Kaneesha are on a baseball team. They each bought a baseball and x pairs of sweat socks. Write an expression

aivan3 [116]

Answer:

Step-by-step explanation:

Helena Violet Kaneesha

1b 1b 1b

x pairs x pairs x pairs

Helena 1b + x pairs of socks

Helena = 1 b(baseball) + $7X ( X is the number of pairs of socks)

Helena ----- $5 + 7X

Since all 3 bought the same thing, multiply the above by 3

answer = 3(5 +7x)

or Distribute

Answer = (3*5) + (3*7x)

3 0

3 years ago

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