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Vlad1618 [11]
3 years ago
9

Consider the inequality X > - 2.5 Determine whether each value of X makes this inequality true Select ALL that apply.

Mathematics
2 answers:
Leno4ka [110]3 years ago
6 0

Answer:

The correct answers are: 0.5, 3, and 10.

Basically, all numbers that are greater than -2.5 can make this inequality true.

Let me know if this helps!

grigory [225]3 years ago
6 0

Answer:

hi

Step-by-step explanation:

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Between what two integers on a number line would \sqrt[3]{35}35 3 be plotted?
ludmilkaskok [199]

Answer:

5 and 6

Step-by-step explanation:

Because 35 is between 25 and 36.

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Solve 5x - 8y = 11 for y.
disa [49]

Answer:

y = \frac{5x-11}{8}

Step-by-step explanation:

Given

5x - 8y = 11 ( subtract 5x from both sides )

- 8y = 11 - 5x ( multiply through by - 1 )

8y = - 11 + 5x = 5x - 11 ( divide both sides by 8 )

y = \frac{5x-11}{8}

3 0
3 years ago
Give the following equations determine if the lines are parallel perpendicular or neither
GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

\frac{6x-5y}{2}=x+1

Cross multiply both sides of the equation.

6x-5y=2(x+1)6x-5y=2x+2

Subtract 6x on both sides of the equation.

6x-5y-6x=2x+2-6x-5y=-4x+2

Divide both sides of the equation by -5.

-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}y=\frac{4}{5}x-\frac{2}{5}

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

-4y-x=4x+5

Add x on both sides of the equation.

-4y-x+x=4x+5+x-4y=5x+5

Divide both sides of the equation by -4.

\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}y=-\frac{5}{4}x-\frac{5}{4}

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

5 0
1 year ago
The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati
Ksivusya [100]
<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

                    \dfrac{24}{25}

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

Perimeter\ of\ R=2(2x+3x)

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

Perimeter=2(L+B) )

Hence, we get:

Perimeter\ of\ R=2(5x)

i.e.

Perimeter\ of\ R=10x

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

\text{Perimeter\ of\ square}=4s

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}

Now, we know that the area of a square is given by:

\text{Area\ of\ square}=s^2

and

\text{Area\ of\ Rectangle}=L\times B

Hence, we get:

\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}

and

\text{Area\ of\ Rectangle}=2x\times 3x

i.e.

\text{Area\ of\ Rectangle}=6x^2

Hence,

Ratio of the area of region R to the area of region S is:

=\dfrac{6x^2}{\dfrac{25x^2}{4}}\\\\=\dfrac{6x^2\times 4}{25x^2}\\\\=\dfrac{24}{25}

6 0
3 years ago
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Denise is helping her dad build a clubhouse that is shaped like a rectangular prism. The height will be 8 ft. and the length wil
Anna35 [415]

Answer: 6=c.

Step-by-step explanation:

First multiply 8 times 6 and get 48 then you divide 48 from 288 and get 6.

3 0
3 years ago
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