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kirill [66]
3 years ago
9

-12 -24 which one is greater or less than​

Mathematics
2 answers:
Simora [160]3 years ago
7 0

Answer:

-12 > -24

Step-by-step explanation:

When the numbers are negative the number that is closer to zero is the greatest

bonufazy [111]3 years ago
7 0

Answer:

<h2><em>-12 is greater than -24 </em></h2><h2><em>or </em></h2><h2><em>-12 > -24</em></h2>

Step-by-step explanation:

Think of a number line, 0 being the middle point separating positive numbers on the right, and negative numbers on the left. The farther left you go down the number line, the smaller the numbers get in value.

With -12 being closer to 0, and -24 being farther down, which makes -24's value decrease. Which therefore makes it smaller.

<em>~~~~~~~~~~~~~~~~~~~~~~~~~</em>

<em>GL Foe  </em>

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Find the slope of the line passing through the points (-9, -9) &amp; (7, -9)
vagabundo [1.1K]

Answer:

There is no slope

Step-by-step explanation:

The equation for finding the slope is:

y2 - y1

------------

x2 - x1

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-9 - (-9)

-----------                <-----------------         Here is your starting equation

7 -  (-9)

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-9 + 9

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7 + 9

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0

---

16

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There is no slope because you can't divide 0 by 16

Hope that helps :)

6 0
3 years ago
Omar and Meg just had business cards made. Omar's printing company charged a one-time setup fee of $5 and then $5 per box of car
ivanzaharov [21]

Answer:

5 boxes each

Step-by-step explanation:

4 0
3 years ago
Need help please answer
fomenos

Answer:62.73

sin-1 8 divide by 9

6 0
3 years ago
(problem 6.13 page 97) Consider a population in which 80% of males and 60% of females are employed. In this population, 55% of i
svp [43]

Answer:

There is a 50.77% probability that no more than one of those chosen is not employed.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they will be employed, or they will not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

We have these following percentages:

55% of the individuals are female.

So 45% of the individuals are male.

80% of males are employed. So 20% of males are unemployed.

60% of females are employed. So 40% of females are unemployed.

If I pick five persons at random from this population, what is the probability that no more than one of those chosen is not employed?

Using the binomial distribution, p is the probability that a person is unemployed. 40% of the females and 20% of the males are unemployed. The population is 55% females and 45% males. So

p = 0.4*0.55 + 0.2*0.45 = 0.31

There are five persons, so n = 5

What is the probability that no more than one of those chosen is not employed?

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.31)^{0}.(0.69)^{5} = 0.1564

P(X = 1) = C_{5,1}.(0.31)^{1}.(0.69)^{4} = 0.3513

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.1564 + 0.3513 = 0.5077

There is a 50.77% probability that no more than one of those chosen is not employed.

7 0
3 years ago
You and two friends share 7 cookies equally.how many cookies do you each get?
NeX [460]
2 1/3 now everyone has the same amount
4 0
4 years ago
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