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stira [4]
3 years ago
15

the cost C (in dollars) of making n watches is represented by C = 15n + 85. How many watches are made when the cost is $385?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
6 0

I believe the answer is 20.

C= 15n + 85

$385= 15n+85

$385-85= 300

300/15= 20

liberstina [14]3 years ago
4 0
20 watches are made since 385 = 15n + 85. 385 - 85 is 300 and 300 divides by 15 is 20.
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Can someone help me I have two more other questions they are 15 points each I just posted them right now! Thanks so much
nlexa [21]

Answer:

$10 coins: 21

$20 coins: 24

Step-by-step explanation:

heyy me again

So we can create 2 equations where

x = number of $10 coins

y = number of $20 coins:

x + y = 45

10x + 20y = 690

we can move equation 1 around so that we can get a value of x

x = 45 - y

now we can substitute x into the second equation

10(45 - y) + 20y = 690

450 - 10y + 20y = 690

10y = 240

y = 24

Now plug in y back into the first equation

x = 45 - y

x = 45 - 24

x = 21

8 0
2 years ago
What is the output of the function f(x) = x + 21 if the input is 4? When the input is 4, the output of f(x) = x + 21 is
notka56 [123]
To find the output when you know the input, just plug the input into the function.

x+21=4+21=25

The output is 25.

Hope this helps!
8 0
3 years ago
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Find the measure of each exterior angle of a regular polygon in which the sum
Basile [38]
Each exterior angle is 11.25°
8 0
3 years ago
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Aloiza [94]
Add the exponents so 3^3 or 27
7 0
2 years ago
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The admission fee is $1.50 for children and $4.00 for adults. If 2700 people enter and $7800 is collected how many children and
mash [69]

Number of children attended is 1200 and number of adults attended is 1500

<h3><u>Solution:</u></h3>

Given that,

Admission fee for each children = $ 1.50

Admission fee for each adult = $ 4.00

Let "c" be the number of children attended

Let "a" be the number of adults attended

Given that 2700 people enter and $7800 is collected

Number of children attended + number of adults attended = 2700

c + a = 2700  -------- eqn 1

Also given that $7800 is collected

Number of children attended x Admission fee for each children + number of adults attended x Admission fee for each adult = 7800

c \times 1.50 + a \times 4 = 7800

1.5c + 4a = 7800 -------- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "c"

From eqn1,

a = 2700 - c ----- eqn 3

Substitute eqn 3 in eqn 2

1.5c + 4(2700 - c) = 7800

1.5c + 10800 - 4c = 7800

-2.5c = -3000

c = 1200

Therefore from eqn 3,

a = 2700 - 1200

a = 1500

Therefore number of children attended = c = 1200

number of adults attended = a = 1500

3 0
3 years ago
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