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Ivanshal [37]
4 years ago
14

Five urns are numbered 3,4,5,6 and 7, respectively. Inside each urn, there are n² dollars where n is the number on the urn.

Mathematics
1 answer:
11111nata11111 [884]4 years ago
5 0

Answer:

0.25 or 25%

Step-by-step explanation:

3, 5 and 7 are prime numbers.

There are two possible outcomes for which the experimenter ends up with exactly twenty-five dollars:

A) Choosing urn 5 (5 x 5 = 25).

P(A) = \frac{1}{5}

B) Choosing urn 4 and then urn 3 ([4 x 4] + [3 x 3] = 25).

P(B)= \frac{1}{5} *\frac{1}{4}=\frac{1}{20}

The probability that the experimenter ends up with exactly $25 is:

P(x=\$25)=P(A)+P(B)= \frac{1}{5}+\frac{1}{20}\\P(x=\$25)=0.25=25\%

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A student has a class that is supposed to end at 9:00am and another that is supposed to begin at 9:10am. Suppose the actual endi
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Answer:

0.8340

Step-by-step explanation:

The aim of this question is to find the probability that the student makes it to the second class prior to when the lecture commences.

Provided that A, B, and C are independent of each other from the full complete question.

Then; we want P(A + C < B)

So A \sim N (2, 1.5)

B \sim N (10, 1)

C \sim N (6, 1)

P(A + C - B < 0)

Since they are normally distributed( i.e. A + C - B)

Then;

E(A + C -B) = E(A) + E(C) - (B)

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E(A + C -B) =  -2

Var(A+C -B) = Var(A) + Var (B) + Var (C)

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Var(A + C -B) = 4.25

The standard deviation = \sqrt{4.25}

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P(A+C-B) = p \Big (Z < \dfrac{0-(-2)}{2.06155} \Big )

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7 0
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A 0.25 mL sample of water drawn from a 5 liter flask contains 1.25 x 10^8 bacteria. Give the approximate number of bacteria in t
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So, 1liter flask contains = \frac{1.25 \times 10^8}{5} =2.5\times 10^7

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0.25 mL contains = 2.5\times 10^7 \times0.25\times 10^{-3} = 6.25\times 10^3

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Answer:

A.

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