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2 years ago

How much energy was absorbed by the water?

Chemistry

2 answers:

Oksanka [162]2 years ago

6 0

4,184 Joules of energy

Lorico [155]2 years ago

4 0

<h2>Answer: <u><em>Precisely, water has to absorb 4,184 Joules of heat (1 calorie) for the temperature of one kilogram of water to increase 1°C.</em></u></h2>

Explanation:

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Arturiano [62]

ENERY AND FORCE AND OUT AND IN

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3 years ago

Select the correct answer.

ivann1987 [24]

Answer:

Explanation:

The electronic configuration of N (7 electrons): 1s² 2s² 2p³.

The orbital 1s is filled with two electrons and their spinning direction is opposite and also electrons of 2s.

3p contains (3 electrons) should fill the 3 orbitals firstly. Every orbital contains 1 electron and be in the same spin direction.

So, the right choice is c.

A is wrong because 2 electrons of 3p are paired in the first orbital before filling every orbital.

B is wrong because the 2 electrons of 1s and 2s are in the same direction and also 2 electrons of 3p are paired in the first orbital before filling every orbital.

D is also wrong the 2 electrons of 1s and 2s are in the same direction and the electron in the second orbital of 3p are in opposite direction of the other 2 electrons.

7 0

3 years ago

Heat is added to a chemical system. Which energy will increase?

dmitriy555 [2]

Answer:

the kinetic energy of the reactant molecules(C)

Explanation: i hope this is the correct answer if this is wrong or incorrect please let me know

8 0

2 years ago

Read 2 more answers

A chemistry student is given 700. mL of a clear aqueous solution at 26.Â° C. He is told an unknown amount of a certain compound

Alex73 [517]

Answer:

The correct answer is - yes, 4.57 g of solute per 100 ml of solution

Explanation:

The correct answer is yes we can calculate the solubility of X in the water at 22.0Â°C. The salt will remain after the evaporate from the dissolved and cooled down at 26Â°C.

Then, the amount of solute dissolved in the 700 ml solution at 26°C is the weighed precipitate: 0.032 kg = 32 g.

Then solublity will be :

32. g solute / 700 ml solution = y / 100 ml solution

⇒ y = 32. g solute × 100 ml solution / 700 ml solution = 4.57 g.

Thus, the answer is 4.57 g of solute per 100 ml of solution.

5 0

2 years ago

A mouse is placed in a sealed chamber with air at 769.0 torr. This chamber is equipped with enough solid KOH to absorb any CO2 a

svlad2 [7]

<u>Answer:</u> The amount of oxygen gas consumed by mouse is 0.202 grams.

<u>Explanation:</u>

We are given:

Initial pressure of air = 769.0 torr

Final pressure of air = 717.1 torr

Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr

To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 51.9 torr

V = Volume of the gas = 2.20 L

T = Temperature of the gas = 292 K

R = Gas constant = $62.364\text{ L. Torr }mol^{-1}K^{-1}$

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

$51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol$

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of oxygen gas = 0.0063 moles

Molar mass of oxygen gas = 32 g/mol

Putting values in above equation, we get:

$0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g$

Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.

5 0

2 years ago