Answer: a) -6, b) 32, c) -48, d) 9, e) -12
Step-by-step explanation:
Since we have given that
A and B are 4 × 4 matrices.
Here,
det (A) = -3
det (B) = 2
We need to find the respective parts:
a) det (AB)

b) det (B⁵ )

c) det (2A)
Since we know that

so, it becomes,

d) 
Since we know that

so, it becomes,

e) det (B⁻¹AB)
As we know that

so, it becomes,

Hence, a) -6, b) 32, c) -48, d) 9, e) -12


- <u>Distance </u><u>between </u><u>the </u><u>house </u><u>and </u><u>tower </u><u>is </u><u>3</u><u>5</u><u> </u><u>m</u>
- <u>The </u><u>height </u><u>of </u><u>the </u><u>tower </u><u>is </u><u>6</u><u>0</u><u> </u><u>m </u>
- <u>The </u><u>height </u><u>of </u><u>the </u><u>house </u><u>is </u><u>2</u><u>5</u><u> </u><u>m</u>

- <u> </u><u>Height</u><u> </u><u>of </u><u>the </u><u>house </u><u>is</u><u> </u><u>2</u><u>5</u><u>m</u>


<u>Therefore</u><u>, </u>



<u>Now</u><u>, </u><u> </u><u>In </u><u>Right </u><u>angled </u><u>ABC</u>





Answer:
15
Step-by-step explanation:
Angle 2 is 2x+10
angle 4 is 4x+80
and from the figure we can understand that when we add these 2 equations
We get
6x+ 90= 180
6x = 180 - 90= 90
6x= 90
x = 90 ÷ 6 = 15
answer = 15
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Y
=
2
y
/3
−
3
x
=
−
y
/3
+
7
Hope this helped!
Csc theta=-2 then theta equals csc^-1(-2) then theta would equal 5pi/6, 7pi/6