A dolphin jumps from the water at an initial velocity of 16 feet per second. The equation h + -16t^2 + 80t models the dolphin's
height at any given time, t. What is the maximum height the dolphin jumps?
1 answer:
Answer:
100feet
Step-by-step explanation:
Given the height reached by a dolphin expressed by the equation is h = -16t^2 + 80t. At maximum height, the velocity is zero, hence;
v(t) = dh/dt = -32t + 80
0 = -32t + 80
32t = 80
t = 80/32
t = 2.5secs
Substitute t = 2.5 into the height formula h = -16t^2 + 80t
h = -16(2.5)^2 + 80(2.5)
h = -100+200
h = 100feet
Hence the maximum height the dolphin jumps is 100feet
You might be interested in
Answer:
2x +5(y+3)
Step-by-step explanation:
this depends on what you want
x+y+x+y+3(y+5)
expanding this, we have;
2x +2y +3y+15
2x +5y +15
2x +5(y+3)
Answer:
Step-by-step explanation:
$27.63 / 2 = $13.82
$13.82 * 0.20 = $2.76
$13.82 + $2.76 = $16.58
Answer:
Can u show the whole question
Answer:
It would be A.
You can trust me because a right angle is 90 degrees, so you would add the two angles.
Answer:
109 metres
Step-by-step explanation:
1. Do 15+36+29 which equals 80
2. Do 189-80 and u get 109
Hope this helps :3