All categories

3 years ago

Find the value of x.

Mathematics

1 answer:

sineoko [7]3 years ago

6 0

Answer:

Step-by-step explanation:

You might be interested in

14. Let R^2 have inner product defined by ((x1,x2), (y,, y2)) 4x1y1 +9x2y2 A. Determine the norm of (-1,2) in this space B. Dete

Vitek1552 [10]

The norm of a vector $\vec x$ is equal to the square root of the inner product of $\vec x$ with itself.

a. $\|(-1,2)\|=\sqrt{\langle(-1,2),(-1,2)\rangle}=\sqrt{4(-1)^2+9(2)^2}=\sqrt{40}=2\sqrt{10}$

b. $\|(3,2)\|=\sqrt{\langle(3,2),(3,2)\rangle}=\sqrt{4(3)^2+9(2)^2}=\sqrt{72}=6\sqrt2$

7 0

3 years ago

HELP ME( PICTURE IS SHOWN WHEN YOU CLICK THE QUESTION

vodka [1.7K]

Answer:

can you mark me as a brainliest and answers c

7 0

2 years ago

Read 2 more answers

Consider a triangle with angles 30o-60o-90o, with hypotenuse of length 2. Calculate the lengths of the other 2 sides and store t

kumpel [21]

Answer:

1.00 and 1.73

Step-by-step explanation:

1) Calculating the 1st and the 2nd leg using trigonometric function sine:

$sin (30^{0})=\frac{c}{2}\Rightarrow \frac{1}{2}=\frac{c}{2}\Rightarrow 2*\frac{1}{2}=2*\frac{c}{2}\Rightarrow c=1\\sin(60^0)=\frac{b}{2}\Rightarrow \frac{\sqrt{3}}{2}=\frac{b}{2}\Rightarrow b=\sqrt{3}\Rightarrow\: b\approx \:1.73$

Once one leg is found there is another way to find the other leg, using Pythagorean Theorem too.

$a^{2}=b^{2}+c^{2}\Rightarrow 2^{2}=b^{2}+1^{2}\Rightarrow 4-1=b^{2}\Rightarrow b=\sqrt{3} b\approx 1.73$

Sides

a hypotenuse: 2.00

-------------------------------

b leg: 1.73

--------------------------------

c leg: 1.00

--------------------------------

4 0

3 years ago

Sienna has a coupon for an additional 15% off her entire purchase at a store. She knows she can solve the expression p-0.15p to

snow_lady [41]

It is B because 100% -15%=.85

5 0

3 years ago

Ill give brainiest for the one who answers all the question

wel

Answer:

Because it will take a lot of time to do

6 0

3 years ago