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Phantasy [73]
3 years ago
8

Which hyperbola has both vertices in the same quadrant?

Mathematics
1 answer:
Serggg [28]3 years ago
4 0

Answer:

Given a hyperbola with an equation:

Foci will have coordinates:

F₁ (xc - c, yc) and F₂ (xc - c, yc)

where c = √(a² + b²)

While given a hyperbola with an equation:

Foci will have coordinates:

F₁ (xc , yc - c) and F₂ (xc , yc - c)

where c = √(b² + a²)

Now, start looking at the equations you are given as a solution and note the option A and C do not represent a hyperbola since they don't have both parenthesis squared.

For option B) you have:

xc = 24

yc = 1

a² = 24² = 576

b² = 7² = 49

Therefore:

c = √(576+49) = √625 = 25

and

F₁(-1 , 1)  F₂(49 , 1)

which are not on the same quadrant.

For option D) you have:

yc = 16

xc = -1

a² = 9² = 81

b² = 12² = 144

Therefore:

c = √(144+81) = √225 = 15

and

F₁(-1 , 1)  F₂(-1 , 31)

which are on the same quadrant.

Hence, the correct answer is b i think

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Answer:

A.

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8 0
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Vanyuwa [196]

Answer:

y=130°

Step-by-step explanation:

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6 0
3 years ago
I don't know what to do
True [87]
Your answer is 1/4, -7/3,-4
8 0
3 years ago
Describe the possible values for x and y when ∣x − y ∣ &gt; 0. What does it mean when ∣x − y ∣ = 0? Can ∣x − y ∣ &lt; 0? Explain
Vilka [71]
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Hope that this helped!
4 0
3 years ago
Can someone please help me with # 2 #13 thanks show work how it's done, please
zavuch27 [327]

Problem 13

10p+10q factors to 10(p+q). If we apply the distributive property, we can distribute the 10 to each term inside (p and q) to get

10(p+q) = (10 times p)+(10 times q) = 10*p + 10*q = 10p+10q

so we get the original expression again. Here 10 is the GCF of the two terms.

--------------------------------------------------------------

Plug p = 1 and q = 2 into the factored form

10*(p+q) = 10*(1+2) = 10*(3) = 30

As a check, let's plug those p,q values into the original expression

10*p+10*q = 10*1+10*2 = 10+20 = 30

We get the same output of 30

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3 years ago
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