Since we know that a number is divisible by 3 if the sum of all digits is divisible by 3.
Let us check which digits will make 371? divisible by 3.
11 is not divisible by 3.
Now let us check other digits as well.
12 is divisible by 3.
15 is also divisible by 3.
18 is divisible by 3 as well.
Therefore, 1, 4 and 7 in tenth place will make our number divisible by 3 and our numbers will be 3711, 3714 and 3717.
Y=x+3
-3x+3(x+3)=4
-3x+3x+9=4
9=4
Since this statement is false, there are no ordered pair solutions to this problem.
Answer:
Multiply 9 by 6
Step-by-step explanation:
7:9 is the ratio
We multiply the first term by 6.
What we do to one side, we do to the other
7*6=42
9*6 = 54
That way we keep the ratio in the same proportion
42:54
1) it must be fulfilled that the denominator is different from zero, then for this expression
x^2 -9 ⇒ x^2-3^2 = (x-3)(x+3)⇒ (x-3)(x+3) = 0 ⇒ x = 3 o x = -3 , the dominium is all numbers reals except 3 and -3
Answer:
3+4+6*2=26
Step-by-step explanation:
hope this helps!
