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polet [3.4K]
3 years ago
15

How do I show the identity of cos(6x) = 2cos^2(3x)-1

Mathematics
1 answer:
notsponge [240]3 years ago
4 0
You are given the function of  identity of cos(6x) = 2cos^2(3x)-1. <span>A sine and cosine function is one of the basic functions encountered in Trigonometry. Sine is equal to the opposite side over hypotenuse whereas the cosine function is equal to the adjacent side over the hypotenuse.</span>

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He has a 1/6 chance.
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10/13 = 8 - 2z/52 Thats the question. Im dyin for help. :)
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Answer:

z = 188

Step-by-step explanation:

1. 10/13 = 8 - 2z/52 (simplify - 2z/52)

10/13 = 8 (- 1/26)*z

2. 10/13 = (- 1/26)*z + 8 (flip for ease in solving)

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3. (- 1/26)*z + 8 = 10/13 (inverse: subtract 8 from each side to isolate variable <em>z</em>)

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(- 1/26)*z = - 94/13 (simplify)

4. (- 1/26)*z = - 94/13 (inverse: multiply both sides by -26/1 to isolate variable <em>z</em>)

<h2>z = 188</h2>
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