3 years ago

How do I show the identity of cos(6x) = 2cos^2(3x)-1

1 answer:

4 0

You are given the function of identity of cos(6x) = 2cos^2(3x)-1. <span>A sine and cosine function is one of the basic functions encountered in Trigonometry. Sine is equal to the opposite side over hypotenuse whereas the cosine function is equal to the adjacent side over the hypotenuse.</span>

You might be interested in

(−7c+8d)0.6 distributive property

Ksivusya [100]

We are given

$(-7c+8d)0.6$

we can use distribute property

Distributive property:

$(A+B)C=A*C+B*C$

so, we can write it as

$(-7c+8d)0.6=-7c*0.6+8d*0.6$

$(-7c+8d)0.6=-7*0.6c+8*0.6d$

now, we can multiply terms

and we get

$(-7c+8d)0.6=-4.2c+4.8d$ ..............Answer

4 0

3 years ago

Read 2 more answers

Help ASAP thank you!! And show work !

RUDIKE [14]

Answer:

c. -2

Step-by-step explanation:

Since f(x) is the regular graph. Since the inverse function flips the x and y coordinates, f inverse of 4 is actually where y=4, not x=4. so the x coordinate where y is 4 is -2.

6 0

3 years ago

What is 8 * 3/4 hour

Pachacha [2.7K]

78 * 3/4 hour,
it is 6 hours

5 0

3 years ago

Read 2 more answers

What are the domain and range of the function f(x)= 1/4(x^3+6^2+5x-4)

alexandr1967 [171]

Answer:

it is 300