Answer:
8 ounces of vinegar
36 ounces of dressing
Step-by-step explanation:
Marco makes his famous salad Jackson by mixing 5 1/4 ounces of olive oil with 1 1/2 ounces of vinegar.
Olive oil Vinegar
5 1/4 1 1/2
28 x
Write a proportion:
![\dfrac{5\frac{1}{4}}{28}=\dfrac{1\frac{1}{2}}{x}\\ \\5\dfrac{1}{4}\cdot x=28\cdot 1\dfrac{1}{2}\ [\text{Cross multiply}]\\ \\\dfrac{21}{4}x=28\cdot \dfrac{3}{2}\\ \\\dfrac{21 x}{4}=42\\ \\x=42\div \dfrac{21}{4}\\ \\x=42\cdot \dfrac{4}{21}\\ \\x=2\cdot 4\\ \\x=8\ ounces](https://tex.z-dn.net/?f=%5Cdfrac%7B5%5Cfrac%7B1%7D%7B4%7D%7D%7B28%7D%3D%5Cdfrac%7B1%5Cfrac%7B1%7D%7B2%7D%7D%7Bx%7D%5C%5C%20%5C%5C5%5Cdfrac%7B1%7D%7B4%7D%5Ccdot%20x%3D28%5Ccdot%201%5Cdfrac%7B1%7D%7B2%7D%5C%20%5B%5Ctext%7BCross%20multiply%7D%5D%5C%5C%20%5C%5C%5Cdfrac%7B21%7D%7B4%7Dx%3D28%5Ccdot%20%5Cdfrac%7B3%7D%7B2%7D%5C%5C%20%5C%5C%5Cdfrac%7B21%20x%7D%7B4%7D%3D42%5C%5C%20%5C%5Cx%3D42%5Cdiv%20%5Cdfrac%7B21%7D%7B4%7D%5C%5C%20%5C%5Cx%3D42%5Ccdot%20%5Cdfrac%7B4%7D%7B21%7D%5C%5C%20%5C%5Cx%3D2%5Ccdot%204%5C%5C%20%5C%5Cx%3D8%5C%20ounces)
Marco will make
ounces of dressing
I’m not doing all that so yeah that’s my answer I
Answer:
6 - 3p
Step-by-step explanation:
The word "product" indicates to multiply 3 and p, and "subtracted from" tells us to use subtraction.
Answer:
Step-by-step explanation:
I am sooo sorry. I do not understand this question though. Can you send a better pic
// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
// The answer is stored in the variable summedvalue.
N = (int) (usernum+1)/2; // maximum number of integers to be summed
int *v = malloc(N*sizeof(int)); // allocate storage for array v
// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
if (k>usernum) { // do not extend v beyond usernum
break;
}
v(count) = k; // assign an odd integer to v, including usenum
count++;
k += 2; // k is an odd number
if k>usernum { // handle usernum as odd or even
k = usernum;
}
}
n = count; // the size of array v.
// Calculate the sum in a for loop
summedvalue = 0; // initialize summedvalue
for (i=0; i<=n; i++) {
summedvalue += v(i);
}
