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vodomira [7]
3 years ago
15

2.8 times the number q is 11.76. Which equation shows the relationship between 2.8, 11.76, and q and then find the value of q? A

. q2.8=11.76q2.8=11.76 B.q = 32.928 2.8q = 11.76 q = 4.2 C.q + 2.8 = 11.76 q = 8.96 D. 11.76q = 2.8 q = 0.24
Mathematics
2 answers:
astra-53 [7]3 years ago
6 0
2.8*q=11.76
2.8q=11.76
q=4.2

I can't see the options very well but it is something along those lines.

Hope this helps :)
marta [7]3 years ago
3 0
I think the answer choice would be B. I can't tell because they look a little jumbled but the answer is:

q2.8 = 11.76 

q = 4.2 

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Andrew [12]

\qquad\qquad\huge\underline{\boxed{\sf Answer}}

Perimeter of given figure is equal to :

Perimeter of square - side length + quarter Circumference of the circle

that is :

\qquad \sf  \dashrightarrow \:(10 \times 4) - (5 + 5) +  \dfrac{2 \pi r}{4}

\qquad \sf  \dashrightarrow \:40- 10 +  \dfrac{3.14 \times 5}{2}

\qquad \sf  \dashrightarrow \:30+  \dfrac{15.7}{2}

\qquad \sf  \dashrightarrow \:30 + 7.85

\qquad \sf  \dashrightarrow \:37.85 \:  \: units

So, the required perimeter is 37.85 units

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2 years ago
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lara [203]

Step-by-step explanation:

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4 0
3 years ago
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A car is 4m long and 1.8 m wide. A model of the car,similar in all respects, is 5 cm long. How wide is it?
Paladinen [302]
x-width\ of\ small\ car\\\\1.8m=180cm\\4m=400cm\\\\From\ proportion:\\\\400\ \ \ -\ \ \ 5\\180\ \ \ -\ \ \ x\\\\400x=900\ \ \ \ |:400\\x=2.25\\\\The\ car\ is\ 2.25cm\ wide.
6 0
4 years ago
HELP 100 POINTS .........SHOW YOUR WORK
Bas_tet [7]
Using Pythagorean theorem

x^2 + 6^2 = sqrt(117)^2

x^2 + 36 = 117

x^2 = 117 -36
x^2 = 81

x = sqrt(81)
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3 0
3 years ago
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A person on tour has dollar 360 for his daily expenses. If he extends his tour for 4 days, he has to cut down his daily expenses
mash [69]

Answer:

The original duration of the tour = 20 days

Step-by-step explanation:

Solution:

Total expenses for the tour = $360

Let the original tour duration be for x days.

So, for x days the total expense = $360

<em>Thus the daily expense in dollars can be given by</em> = \frac{360}{x}

Tour extension and effect on daily expenses.

The tour is extended by 4 days.

<em>Tour duration now</em> = (x+4) days

On extension, his daily expense is cut by $3

<em>New daily expense in dollars </em>= (\frac{360}{x}-3)

Total expense in dollars can now be given as:  (x+4)(\frac{360}{x}-3)

Simplifying by using distribution (FOIL).

(x.\frac{360}{x})+(x(-3)+(4.\frac{360}{x})+(4(-3))

360-3x+\frac{1440}{x}-12

348-3x+\frac{1440}{x}

We know total expense remains the same which is = $360.

So, we have the equation as:

348-3x+\frac{1440}{x}=360

Multiplying each term with x to remove fractions.

348x-3x^2+1440=360x

Subtracting 348x both sides

348x-348x-3x^2+1440=360x-348x

-3x^2+1440=12x

Dividing each term with -3.

\frac{-3x^2}{-3}+\frac{1440}{-3}=\frac{12x}{-3}

x^2-480=-4x

Adding 4x both sides.

x^2+4x-480=-4x+4x

x^2+4x-480=0

Solving using quadratic formula.

For a quadratic equation: ax^2+bx+c=0

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Plugging in values from the equation we got.

x=\frac{-4\pm\sqrt{(4)^2-4(1)(-480)}}{2(1)}

x=\frac{-4\pm\sqrt{16+1920}}{2}

x=\frac{-4\pm\sqrt{1936}}{2}

x=\frac{-4\pm44}{2}

So, we have

x=\frac{-4+44}{2}   and x=\frac{-4-44}{2}

x=\frac{40}{2}   and x=\frac{-48}{2}

∴ x=20           and x=-24

Since number of days cannot be negative, so we take x=20 as the solution for the equation.

Thus, the original duration of the tour = 20 days

6 0
3 years ago
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