Answer:
a.
and 
Step-by-step explanation:
Let x be the larger number and y be the smaller number.
We have been given that one number is 4 more than another. We can represent this information in an equation as:

We can manipulate this equation as:


We are also told that the sum of both numbers is 60. We can represent this information in an equation as:

Upon looking at our given choices, we can see that option 'a' is the correct choice.
Answer:
43.96
(i used 3.14 for pie)
Step-by-step explanation:
2 x 3.99 = 7.98
3 x 4.49 = 13.47
1 x 4.99 = 4.99
Total: 26.44
50.00 - 26.44 = 23.56
F(4)=(4-1)+2*4=11...
This seems a bit too easy though, did you mean f(n)=f(n-1)+2n ? In this case :
f(1)=16
f(2)=16+2*2=20
f(3)=20+2*3=26
f(4)=26+2*4=34
![h(x)=(f\circ g)(x)\\\\h(x)=\sqrt[3]{x+3};\ f(x)=\sqrt[3]{x+2}\\\\h(x)=\sqrt[3]{x+1+2}=\sqrt[3]{(x+1)+2}=\sqrt[3]{g(x)+2}\to \boxed{g(x)=x+1}](https://tex.z-dn.net/?f=h%28x%29%3D%28f%5Ccirc%20g%29%28x%29%5C%5C%5C%5Ch%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B3%7D%3B%5C%20f%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D%5C%5C%5C%5Ch%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B1%2B2%7D%3D%5Csqrt%5B3%5D%7B%28x%2B1%29%2B2%7D%3D%5Csqrt%5B3%5D%7Bg%28x%29%2B2%7D%5Cto%20%5Cboxed%7Bg%28x%29%3Dx%2B1%7D)
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