Answer:
j-4 is how you show 4 less than a number j
 
        
             
        
        
        
V=x³-7x+6, V=(x-2)(x+3)*h
(x-2)(x+3)*h=x³-7x+6
h{x²+x-6}=x³-7x+6
h=(x³-7x+6)/(x²+x-6)
Therefore h=x-1
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Check answer:
V=(x-2)(x+3)(x-1)
=(x-1)(x²+x-6)
=x(x²+x-6)-1(x²+x-6)
=x³+x²-6x-x²-x+6
=x³-6x-x+6
=x³-7x+6
        
             
        
        
        
Answer:

Step-by-step explanation:
![[-5+(-7)]^2-(7+3)^2](https://tex.z-dn.net/?f=%5B-5%2B%28-7%29%5D%5E2-%287%2B3%29%5E2)
Resolving Parenthesis

=> 44
 
        
                    
             
        
        
        
Answer:
35
Step-by-step explanation:
write 5 in N's place
5^2+2×5×1
25+10
35