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2 years ago

The bookstore has books on sale for $5. Miguel has $28 in his wallet. How many books can he buy?

Mathematics

1 answer:

hammer [34]2 years ago

7 0

Answer:

Miguel can by 5 books with $3 leftover

Step-by-step explanation:

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The height of three students in the class are given below. Order the students from shortest to tallest.

miskamm [114]

Answer:

Janis, Carl, Catherine

Step-by-step explanation:

janis=1.666

carl=1.7

catherine=2.333

7 0

1 year ago

At a local preschool, there is a ratio of 3 boys to every 4 girls. If there are 245 total preschoolers enrolled, then how many a

Reika [66]

Set up the equation by writing the number of students in the ratio as a fraction:

3/4= (245-x)/x Cross multiply:

3x= 4(245-x) Multiply on right:

3x= 980-4x Add 4x on both sides:

7x= 980 Divide both sides by 7:

x= 140 this is how many girls there are. And:

245-140= 105= boys

5 0

2 years ago

Read 2 more answers

What is 7/10 divided by 2

vodka [1.7K]

Answer:

7/20

Step-by-step explanation:

7/10 ÷ 2/1 is the same as 7/10 * 1/2 which is 7/20

3 0

2 years ago

How to find out 4 x 754 by using two methods

baherus [9]

You can use expanded form: 4 X 700, 4 X 50, 4 X 4, = 3016.

You can use the Distributive Property of Multiplication: (4 X 500) + (4 X 254) = 3016.

4 0

2 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$