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viktelen [127]
3 years ago
6

If x = -6, which inequality is true? A -5-3x>10 B -3-5x 13 D 2-x<-3

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0
The answer is B -3-5x < 13
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The frequency table shows the scores from rolling a dice 10 times work out the mean
chubhunter [2.5K]
<h3>Answer:   3.8</h3>

==========================================================

Explanation:

For each row, multiply the values straight across.

  • Row one: 1*1 = 1
  • Row two: 2*3 = 6
  • Row three: 3*0 = 0
  • Row four: 4*2 = 8
  • Row five: 5*1 = 5
  • Row six: 6*3 = 18

The list of products we got were: 1, 6, 0, 8, 5, 18

Add up those products to get: 1+6+0+8+5+18 = 38

The value 38 represents the total value if we were to add up all of the results of each die roll (it shows up again in the next section). We divide this over the total frequency, which is the sum of everything in the second column. That total frequency being 1+3+0+2+1+3 = 10.

So the mean is 38/10 = 3.8

-------------

A longer way to do this is to expand each value based on the frequency shown. The value '1' shows up one time, so we just write "1" once. The value "2" shows up three times, so we write "2" three times. So far the list is {1,2,2,2}

The value "3" doesn't show up at all, so we skip to "4" which shows up twice. The updated data set so far is {1,2,2,2,4,4}

Then it updates again to {1,2,2,2,4,4,5} when we account for the single "5"

Finally, the fully up to date list of values is {1,2,2,2,4,4,5,6,6,6}

Computing the mean of this set has us add up the values to get 1+2+2+2+4+4+5+6+6+6 = 38. We have that "38" show up again, which is not a coincidence. We divide over 10 because there are ten values in the fully up to date list shown above. So this is a different method to get the mean of 3.8

If you prefer this second method, then you should use it; however, I recommend the first method as it's faster and more efficient. It might be handy to try both methods just for practice.

6 0
3 years ago
In ΔIJK, i = 340 cm, ∠I=120° and ∠J=59°. Find the area of ΔIJK, to the nearest 10th of a square centimeter.
vlada-n [284]

Answer:

8900 is the correct answer

7 0
3 years ago
Choose the equation that represents the line that passes through the point (−1, 6) and has a slope of −3.
guapka [62]

Answer:

Step-by-step explanation:

The equation of a line is y=mx+b, where m is the slope and b is the y-intercept. y and x are the y and x values of any point respectively.

The information we have:

y = 6

x = -1

m = -3

6 = -3*-1 + b

6 = 3 + b

b = 3

So now we know that m = -3 and b = 3

y and x were 6 and -1 in this case but we need an equation that works for any point on the line so we can keep y and x just as it is (variables, not numbers).

The final equation is:

y = -3x + 3

4 0
3 years ago
Read 2 more answers
If A, B, and C are integers between 1 and 10 (inclusive), how many different combinations of A, B, and C exist such that A
Marianna [84]

\fontsize{18}{10}{\textup{\textbf{The number of different combinations is 120.}}}

Step-by-step explanation:

A, B and C are integers between 1 and 10  such that A<B<C.

The value of A can be minimum 1 and maximum 8.

If A = 1, B = 2, then C can be one of 3, 4, 5, 6, 7, 8, 9, 10 (8 options).

If A = 1, B = 3, then C has 7 options (4, 5, 6, 7, 8, 9, 10).

If A = 1, B = 4, then C has 6 options (5, 6, 7, 8, 9, 10).

If A = 1, B = 5, then C has 5 options (6, 7, 8, 10).

If A = 1, B = 6, then C has 4 options (7, 8, 9, 10).

If A = 1, B = 7, then C has 3 options (8, 9, 10).

If A = 1, B = 8, then C has 2 options (9, 10).

If A = 1, B = 9, then C has 1 option (10).

So, if A = 1, then the number of combinations is

n_1=1+2+3+4+5+6+7+8=\dfrac{8(8+1)}{2}=36.

Similarly, if A = 2, then the number of combinations is

n_2=1+2+3+4+5+6+7=\dfrac{7(7+1)}{2}=28.

If A = 3, then the number of combinations is

n_3=1+2+3+4+5+6=\dfrac{6(6+1)}{2}=21.

If A = 4, then the number of combinations is

n_4=1+2+3+4+5=\dfrac{5(5+1)}{2}=15.

If A = 5, then the number of combinations is

n_5=1+2+3+4=\dfrac{4(4+1)}{2}=10.

If A = 6, then the number of combinations is

n_6=1+2+3=\dfrac{3(3+1)}{2}=6.

If A = 7, then the number of combinations is

n_7=1+2=\dfrac{2(2+1)}{2}=3.

If A = 3, then the number of combinations is

n_8=1.

Therefore, the total number of combinations is

n\\\\=n_1+n_2+n_3+n_4+n_5+n_6+n_7+n_8\\\\=36+28+21+15+10+6+3+1\\\\=120.

Thus, the required number of different combinations is 120.

Learn more#

Question : ow many types of zygotic combinations are possible between a cross AaBBCcDd × AAbbCcDD?

Link : https://brainly.in/question/4909567.

8 0
3 years ago
Can anyone help me with this
poizon [28]

Answer:

180 is your answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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