Answer:
1/3 of black F2 progeny will be homozygous.
Explanation:
Here, BB = black coat color = true breeding dominant black strain
bb = white coat color = true breeding recessive white strain
When true breeding black and white guinea pigs are mated to give F1 progeny:
BB X bb = Bb ( all black guinea pigs )
When two of the F1 guinea pigs are mated to give F2 progeny:
Bb X Bb = BB, Bb, Bb, bb
F2 progeny has 3/4 progeny as black (BB and Bb) . Out of them 1/3 are homozygous and 2/3 are heterozygous.
Hence, 1/3 of black F2 progeny will be homozygous.
Answer:
The correct answer will be option-C.
Explanation:
The production of ATP from ADP and Pi (inorganic phosphate) catalyzed by an enzyme known as ATP synthase.
ATP synthase is made up of two main regions called F₀ and F₁ in which F₀ is embedded in the membrane and acts as a pump through which proton flux takes place. The F₁ unit is the rotating unit of the ATP synthase which rotates due to energy provides by the protons during proton flux.
When proton moves through F₀ unit down their concentration gradient, it provides energy to the F₁ subunits which bind ADP and inorganic phosphate to release ATP.
Thus, Option-C is the correct answer.
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A zygote is the product of fertilization. The diploid zygotes of the four organisms seen here all underwent mitosis and differentiation in order to produce the four very different embryos. The differentiation of cells during embryogenesis is the key to cell, tissue, organ, and organism identity. Once an egg is fertilized by a sperm, a zygote is formed. The zygote divides into multiple cells by mitosis, triggering the beginning of embryonic differentiation. <span />
This is because elements are pure substances with only one atom. When two or more elements are combined, you get compound elements; which allows for more substances to be created.
