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xeze [42]
3 years ago
7

E varies directly with The square root of C. If E=40 When C=25 find: E when C = 49 ( Please help ASAP I need to hand this in tom

orrow ! )
Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

E = 56

Step-by-step explanation:

Given that E varies directly with \sqrt{C} then the equation relating them is

E = k\sqrt{C} ← k is the constant of variation

To find k use the condition E = 40 when C = 25

k = \frac{E}{\sqrt{C} } = \frac{40}{\sqrt{25} } = \frac{40}{5} = 8, thus

E = 8\sqrt{C} ← equation of variation

When C = 49, then

E = 8 × \sqrt{49} = 8 × 7 = 56

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3 years ago
Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step
GalinKa [24]

Answer:

Jada should have multiplied both sides of the equation by 108.

Step-by-step explanation:

The question is incomplete. Find the complete question in the comment section.

Given the equation -4/9 = x/108, in order to determine Jada's error, we need to solve in our own way as shown:

Step 1: Multiply both sides of the equation by -9/4 as shown:

-4/9 × -9/4 = x/108 × -9/4

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Cross multiplying

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It can also be solved like this:

Given -4/9 = x/108

Multiply both sides by 108 to have:

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-4/9 * 108 = 108x/108

-432/9 = x

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Jada should have simply follow the second calculation by multiplying both sides of the equation by 108 as shown.

7 0
3 years ago
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3x + 8 = 0
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3 years ago
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