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zheka24 [161]
3 years ago
5

There are five performers who will present their comedy acts this weekend at a comedy club. How many different ways are there to

schedule their​ appearances?
Mathematics
1 answer:
kupik [55]3 years ago
3 0
I believe its 5 but if there are answer choices that would help us answer them better.
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Explain how to use the unit rate to make a table​
xxTIMURxx [149]

Answer:

to make a unit rate using a table you would take an input/output from a table and convert it into a fraction. Then you would take that fraction and simplify it. Sometimes you might have to choose a new input/output in order to make the simplification easier.

Example-

2:4

4:8

6:12

8:16

        Turn one into a fraction

4/8

       Simplify

1/2

7 0
3 years ago
A bag contains 10 counters
juin [17]

44%

6/10 = 3/5

3/5 x 1/10 = 3/50

3/50 x 1/10 = 3/500

3/500 / 2/6 = 44/100

7 0
3 years ago
Find the quotient of these Complex Numbers. <br><br><br> (5-i) / (3+2i)
JulsSmile [24]

Let the given complex number

z = x + ix = \dfrac{5-i}{3+2i}

We have to find the standard form of complex number.

Solution:

∴ x + iy = \dfrac{5-i}{3+2i}

Rationalising numerator part of complex number, we get

x + iy = \dfrac{5-i}{3+2i}\times \dfrac{3-2i}{3-2i}

⇒ x + iy = \dfrac{(5-i)(3-2i)}{3^2-(2i)^2}

Using the algebraic identity:

(a + b)(a - b) = a^{2} - b^{2}

⇒ x + iy = \dfrac{15-10i-3i+2i^2}{9-4i^2}

⇒ x + iy = \dfrac{15-13i+2(-1)}{9-4(-1)} [ ∵ i^{2} =-1]

⇒ x + iy = \dfrac{15-2-13i}{9+4}

⇒ x + iy = \dfrac{13-13i}{13}

⇒ x + iy = \dfrac{13(1-i)}{13}

⇒ x + iy = 1 - i

Thus, the given complex number in standard form as "1 - i".

5 0
3 years ago
Whats the distance between coordinates (-6,8) and (-6,-3)
insens350 [35]

Answer:

there away from eachother for 5 spaces.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve the following problems. Be sure to indicate if a solution is to be rejected based on the contextual situation.
aleksklad [387]

Answer:

1. 5/3 cm

2. 10 in

Step-by-step explanation:

1. The length of a rectangle is 4 cm more than 3 times its width.

Let the length be L and the width B

Then,

L = 4 + 3B

If the area of the rectangle is 15 cm2

Area = LB = 15

B(4 +3B) = 15

3B² + 4B - 15 = 0

3B² - 5B + 9B - 15 = 0

B(3B - 5) + 3(3B - 5) = 0

(3B - 5)(B + 3) = 0

3B - 5 =  or B + 3 = 0

B = 5/3 or -3

since B cannot be negative, B = 5/3 cm

2. The ratio of length to width in a rectangle is 2 ∶ 3.

Let the length be L and the width B

Then,

L/B = 2/3

2B = 3L, B = (3/2)L

when the area is 150 in2.

Area = LB = 150

(3/2)L² = 150

L² = 150×2÷3

L² = 100

L = √100

L = ±10

since the length cannot be negative, L = 10 in

4 0
3 years ago
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