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3 years ago

Please 16-20. I really have no clue how to do it. Please step by step.

Mathematics

1 answer:

marishachu [46]3 years ago

8 0

16. 40°
17.125°
18.135°
19. x=96° 2x-50=142° x+40=136° x+20=116°
20. x=25° x+40=65° 2x+20=70° 3x=75° 6x=150°

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The question is in the picture. Plz helppp it is due tonight

Mkey [24]

Answer:

Step-by-step explanation:

We're given one equation, we have to find the other equation and solve each for 200, and whichever has the lower x is the winner

for Jayden we are given

$(0, 48), (1, 56), (2, 64), (3, 72), (4, 80)$

This looks to be a line. The y values are each separated by a common difference

We can use two points to describe the line

$m = \frac{y_2-y_1}{x_2-x_1} = \frac{80-48}{4-0} = \frac{32}{4} = 8\\ K = 8m + b\\48 = 8(0) + b\\b = 48\\so\\K = 8m + 48$

Now we can set both $K = 8m + 48$ and $K = m^2 + 10$ equal to 200

$200 = 8m + 48\\152 = 8m \\m = \frac{152}{8} = 19$

$200 = m^2 + 10\\m^2 = 190\\m = \sqrt{190} = 13.784$

Keiko's blog will reach 200 subscribers fastest.

7 0

3 years ago

Solve the compound inequality 6b < 42 or 4b + 12 > 8

swat32

Answer:

b<7

Step-by-step explanation:

6b<42

42/6 = 7

b<7

3 0

3 years ago

Help me with question a please ! With full workings !

frosja888 [35]

A)

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
P&({{ 0.5}}\quad ,&{{ 0}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$

$\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}$

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)

c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
% (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}$

$\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad \right. \uparrow\\
\textit{point-slope form}$

7 0

3 years ago

Estimate the awnser to 17 x 193

8_murik_8 [283]

I think i know this one. it's 3,281.

8 0

3 years ago

Read 2 more answers

I need help solving this

Alekssandra [29.7K]

Answer:

I'd say x is 15-16