17÷25=0.68
So it terminates.
Answer:
i need pointssssss plssss
Answer:
(a) t = 7 sec approximately; (b) t = 6 sec
Step-by-step explanation:
(a) Set h(t)= -16(t-3)^2 + 288 = 0 and solve for t:
16(t-3)^2 = 288
After simplification, this becomes (t - 3)^2 = 18, or t - 3 = ±3√2.
Because t can be only zero or positive, t = 3 + 3√2 = 7 seconds
(b) Solve h(t)= -16(t-3)^2 + 288 = 150:
-16(t-3)^2 = - 162
or (t - 3)^2 = 10.125, or
t - 3 = ±3.18, or, finally, t = 6.18 sec (discard t = -0.18 sec)
Answer:
the sidewalk speed q = 3km/hr
the tortoise speed p is 1.5 km/hr
Step-by-step explanation:
From the given information:
let the speed of the tortoise be p & the speed of the sidewalk be q
she's been running for 40 minutes (40/60 = 2/3) and that she's travelled 3 kilometres
Thus,
p + q = 
p + q = 9/2
p + q = 4.5 ----- (1)
when returning, she travelled 3km in 2 hours
i.e. -p + q = 3/2
-p + q = 1.5 ----- (2)
Thus, by using the elimination method for equation (1) and (2)
p + q = 4.5 ----- (1)
<u>-p + q = 1.5 ----- (2) </u>
<u> 2q = 6 </u>
q = 6/2
q = 3 km/hr
From equation (1)
p + q = 4.5
p + 3 = 4.5
p = 4.5 - 3
p = 1.5 km/hr
Therefore, the sidewalk speed q = 3km/hr and the tortoise speed p is 1.5 km/hr