Answer:
4.806 g ≤ n ≤ 5.194 where n is the mass of a nickle.
Step-by-step explanation:
The problem tells us the weight can vary by .194 g, this means it can be up to .194 lighter and 194 heavier. Well what value is .194 lighter and .194 heavier? 4.806 and 5.194 respectively. So that means a nickle can be anywhere in that range, which tells us the inequality.
First find the new coordinates for P and Q after the translations:
P'(2 + 3, 4 - 4) = P'(5, 0)
Q'(-3 + 3, 2 - 4) = Q'(0, -2)
Now, find the slope from this:
(0 - (-2))/(5 - 0) = 2/5
The slope has remained the same. It is important to note that after any translation, the slope will always remain the same. However, this is not always so for rotations and reflections.
Vbox-vspheres
vbox=, I assume we are dealing with l=w=h
so
v=lwh=12^3=1728
vsphere=(4/3)pir^3
r=3
vsphere=(4/3)pi3^3=4pi9=36pi
8 of them so
8 times 36pi=288pi or about 904.7786842338604526772412943845 cubic inches
vbox-sphere=1728-904.7786842338604526772412943845=823.2213157661395473227587056155
space filled by packing beads is about 823.22 cubic inches
beads percent is 823.2213157661395473227587056155/1728 times 100=47.64% filled by beads
Answer:
haha thanks for the points btw the answer is. h2t=th6
Step-by-step explanation: