Round 6.512459 to the nearest ten-thousandth

LuckyWell [14K]

8 goes into 144 18 times

6 0

3 years ago

Jimmy is selling bracelets for $1.50. So far she has earned $120. She needs to earn more than $135 in order to meet her goal. Ho

Tema [17]

Selling 90 would reach her goal of $135 so she would need to sell 91 to exceed her goal

135/1.5=90 so 91*1.5=136.5

4 0

3 years ago

(1/2 + 3/2)² + (2/3 x 1/2)³

docker41 [41]

The result of the mathematical expression given as follows: (1/2 + 3/2)² + (2/3 x 1/2)³ is 5.59 or 5⅔.

<h3>How to calculate mathematical expressions?</h3>

According to this question, the following expression is given to solve: (1/2 + 3/2)² + (2/3 x 1/2)³

First, we solve the both parts as follows:

½ + 3/2 = 2
⅔ + ½ = 1..16

Next, we solve the exponential function as follows:

= (2)² + (1.16)³

= 4 + 1.59

= 5.59 or 5⅔

Therefore, the result of the mathematical expression given as follows: (1/2 + 3/2)² + (2/3 x 1/2)³ is 5.59 or 5⅔.

Learn more about mathematical expression at: brainly.com/question/1703934

#SPJ1

5 0

2 years ago

Work out the value of angle x and how ??

frutty [35]

Answer:

160 degrees

Step-by-step explanation:

Step 1: A straight line is 180 degrees. So 180 - 100, is 80 degrees. as the opposite angle measurement of the 100 degree.

Step 2: An isosceles triangle has two equal angle measurements, so two of its angles are 80 degrees.

Step 3: All angles in a triangle equal 180 degrees. So add them up (we will call the missing angle, Z) 180 = 80+80+Z. which equals 180= 160+z

Step 4: Solve it. You subtract 160 from both side which comes out to 20 = Z.

Step 5: Now you have the opposite angle of X. Going back to step 1, A straight angle is 180 degrees. 180 - 20 = 160. X = 160 degrees

6 0

3 years ago

Use the discriminant to determine the number of solutions to the quadratic equation 3x^2+5x=-1

kari74 [83]

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

<u>Background of the Discriminant</u>

The discriminant $b^2-4ac$ applies to quadratic equations when they are organised in standard form: $ax^2+bx+c=0$ .

All quadratic equations can be solved with the quadratic formula: $x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}$ .

When $b^2-4ac$ is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

<u>Solving the Problem</u>

We're given the above equation. It hasn't been organised completely in $ax^2+bx+c=0$ , but we can change that by adding 1 to both sides to make the right side equal to 0:

$3x^2+5x+1=0$ <u />

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

$D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13$

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

4 0

3 years ago