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3 years ago

The sum of two numbers is 12. the difference of the same two numbers is -4 . find the two numbers

Mathematics

1 answer:

gtnhenbr [62]3 years ago

5 0

Answer:

(4,8)

x=4

y=8

Step-by-step explanation:

x is the first number

y is the second number

x+y=12

x-y= -4

Let's add y and 4 to the second equation to get y by itself

x+4=y

We can substitute this value in for y in the first equation

x+x+4=12

2x=8

x=4

We can then use x=4 and plug that into any equation

4+y=12

y=8

The answer is (4,8)

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2 years ago

Simplify (8^4/10^4)^-1/4using rational exponents

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Answer:

$(\frac{8^4}{10^4} )^{-\frac{1}{4} }$ = $\frac{5}{4}$

Step-by-step explanation:

Explanation

Given

$(\frac{8^4}{10^4} )^{-\frac{1}{4} }$

By using algebra formulas

$(\frac{a}{b} )^{m} = \frac{a^m}{b^n}$

$(\frac{8^4}{10^4} )^{-\frac{1}{4} } = \frac{(8^{4})^{\frac{-1}{4} } }{(10^{4} )^{\frac{-1}{4} } }$

$(a^{m} )^{n} = a^{mn}$

$\frac{(8^{4})^{\frac{-1}{4} } }{(10^{4} )^{\frac{-1}{4} } } = \frac{8^{4X\frac{-1}{4} } }{10^{4 X\frac{-1}{4} } }$

= $\frac{8^{-1} }{10^{-1} }$

$= \frac{10}{8} \\= \frac{5}{4}$

Final answer:-

$(\frac{8^4}{10^4} )^{-\frac{1}{4} }$ = $\frac{5}{4}$

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