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xeze [42]
3 years ago
6

Miguel baked 40 cookies with 8 ounces of chocolate chips. How many cookies could he bake with one ounce of chocolate chips ?

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0
8 ounces of chocolate chips can be used to make 40 cookies so
1 ounce of chocolat3 chips can be used to make 40÷8=5 cookies
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Please help me identify the terms and like terms
sergey [27]

Step-by-step explanation:

can you send a new picture I can't see the whole problem

4 0
3 years ago
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Please write the function(x) from the given rules:a. Twice the input value plus three. B. The input value minus five. C. To get
Bas_tet [7]

Answer:

A) f(x) = 2x + 3

B) f(x) = x - 5

C) f(x) = 2x + 4

Step-by-step explanation:

To find - Please write the function(x) from the given rules:

              A) Twice the input value plus three.

              B) The input value minus five.

              C) To get the output, multiply the input by two, then add four.

Proof -

Let us assume that the input = x

The output = f(x)

Now,

A)

f(x) = 2x + 3

B)

f(x) = x - 5

C)

f(x) = 2x + 4

8 0
3 years ago
A local little league has a total of 95 players, of whom 80% are right handed. How many right handed players are there?
timurjin [86]

100-80=20

95-20=75

75+1=76

the answer is 76 dunno if that's how you're supposed to get the answer but I checked it so :/

edit I did the wrong calculations, but I got the right answer

4 0
3 years ago
The hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh
konstantin123 [22]

Answer:

33 copies were paperback and 12 were hardcover.

Step-by-step explanation:

Let h represent the number of hardcover copies and p represent the number of paperback copies.

We know that the total number of copies was 45; this gives us the equation

h+p = 45

We know that each hardcover copy is 7 ounces; this gives us the expression 7h.

We also know that each paperback copy is 5 ounces; this gives us the expression 5p.

We know that the total weight was 249 ounces; this gives us the equation

7h+5p = 249

Together we have the system

\left \{ {{h+p=45} \atop {7h+5p=249}} \right.

We will use elimination to solve this.  First we will make the coefficients of the variable p the same; to do this, we will multiply the top equation by 5:

\left \{ {{5(h+p=45)} \atop {7h+5p=249}} \right. \\\\\left \{ {{5h+5p=225} \atop {7h+5p=249}} \right.

To eliminate p, we will subtract the equations:

\left \{ {{5h+5p=225} \atop {-(7h+5p=249)}} \right. \\\\-2h=-24

Divide both sides by -2:

-2h/-2 = -24/-2

h = 12

There were 12 hardcover copies sold.

Substitute this into our first equation:

12+p=45

Subtract 12 from each side:

12+p-12 = 45-12

p = 33

There were 33 paperback copies sold.

3 0
4 years ago
Read 2 more answers
Evaluate if m = 16 and p = 2.<br> 1<br> 2<br> m + 3p<br> A) 10 <br> B) 14 <br> C) 18 <br> D) 48
Ivenika [448]
Put the values of m and p to the expression:

\dfrac{1}{2}m+3p\\\\m=16;\ p=2\\\\\dfrac{1}{2}\cdot16+3\cdot2=8+6=14\to B)

4 0
3 years ago
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