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3 years ago

5

Pam had some toy cars. She got 4 more cars. Then her friend gave her 2 more cars. Now Pam has 18 toy cars in all. Which equation

shows this word problem? O A. A. 0 +4+2 = 18 О B. D +4- 2 = 18 O + C. 4+ 2 + 18 = 0 O D. 4+2 – 18 = 1

1 answer:

grigory [225]3 years ago

5 0

A behsnsnnfnfnfhdbdbdnd hdjdns. Dhjdns fjjd rush d end d s

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A medical website states that 40% of U.S. adults are registered organ donors. A researcher believes that the proportion is too h

alexgriva [62]

Answer:

Pvalue = 0.193

There is not enough evidence to conclude that the proportion of registered organ donors is less than 40%

Step-by-step explanation:

H0 : p = 0.4

H1 : p < 0.4

Test statistic :

z=pˆ−p/√p(1−p)/n

pˆ = 74 / 200 = 0.37

Z = (0.37 - 0.40) / √(0.40(1 - 0.40) / 200

Z = - 0.03 / √0.0012

Z = - 0.03 / 0.0346410

Z = - 0.866

Test statistic = -0.866

The Pvalue :

P(Z < -0.866) = 0.193

α - level = 0.05

If Pvalue < α ; Reject H0

Since Pvalue > α ; There is not enough evidence to conclude that the proportion of registered organ donors is less than 40%

3 0

2 years ago

Find each sum.Write in simplest form. 2/6+3/6= 3/8+3/8= 1/4+1/4= 5/12+3/12

Svet_ta [14]

2/6+3/6= 5/6
3/8+3/8= 3/4
1/4+1/4= 1/2
5/12+3/12= 2/3

Hope this helps

4 0

4 years ago

CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars

velikii [3]

Answer:

P(939.6 < X < 972.5) = 0.6469

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

CNNBC recently reported that the mean annual cost of auto insurance is 965 dollars. Assume the standard deviation is 113 dollars.

This means that $\mu = 965, \sigma = 113$

Sample of 57:

This means that $n = 57, s = \frac{113}{\sqrt{57}} = 14.97$

Find the probability that a single randomly selected policy has a mean value between 939.6 and 972.5 dollars.

This is the pvalue of Z when X = 972.5 subtracted by the pvalue of Z when X = 939.6. So

X = 972.5

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{972.5 - 965}{14.97}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

X = 939.6

$Z = \frac{X - \mu}{s}$

$Z = \frac{939.6 - 965}{14.97}$

$Z = -1.7$

$Z = -1.7$ has a pvalue of 0.0446

0.6915 - 0.0446 = 0.6469

So

P(939.6 < X < 972.5) = 0.6469

3 0

2 years ago

62 is 10 times larger than what?

NARA [144]

To find a number 10 times smaller than 62 simply move the decimal point one place to the left.

The decimal point in 62 is at the end of the number. 62. becomes 6.2 if we move the decimal one place back.

5 0

3 years ago

Read 2 more answers

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

3 years ago