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3 years ago

What number would be ten times more than 3,162

Mathematics

2 answers:

miv72 [106K]3 years ago

8 0

3,162 x 10 = 31,620, you just add one zero

Andrew [12]3 years ago

8 0

31,620 easy and simple. You could also use a calculator for this.

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M=2 and containing the point (7,6)

Law Incorporation [45]

Answer:

$the \: equation \: of \: the \: line \: is \to \\ \boxed{ \underline{y = 2x - 8 }}$

Step-by-step explanation:

$according \: to \: the \: provided \: info : \\ the \: equation \: of \: the \: line \: is \to \\ y - y_{1} = m(x - x_{1}) \\ y - 6 = 2(x -7) \\ y = 2x - 14 + 6 \\ \underline{y = 2x - 8 }$

7 0

3 years ago

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Given f(x) = 10 -2xfind f(7). –4 3 7 56

strojnjashka [21]

Answer: $f(7)=-4$

Step-by-step explanation:

1. You have the following function given in the problem:

$f(x)=10-2x$

2. Then, to find $f(7)$ asked in the exercise, you only need to substitute $x=7$ (which is the input value) into the given function.

3. Therefore, keeping the above on mind, you obtain that $f(7)$ is:

$x=7$

$f(7)=10-2(7)$

$f(7)=10-14$

$f(7)=-4$

3 0

3 years ago

Read 2 more answers

The product of some negative number and 5 less than three times that number is 12. Find the number.

miv72 [106K]

(x)(3x - 5) = 12
3x^2 - 5x = 12
3x^2 - 5x - 12 = 0
(x - 3)(3x + 4) = 0
x = 3, -4/3
The answer must be negative so the number is -4/3.

Hope this helps!

4 0

4 years ago

4 less than a number n is - 15 as a equation

Nikitich [7]

Answer:

I believe the equation would be n - 2 = -15.

Step-by-step explanation:

"4 less than a number (n)" is subtraction. You can write it as "n minus 4". "is -15" means this is the difference. This can also be written as "equals -15".

n - 4 = -15

Hope this helps,

♥.A.W.E.S.W.A.N.♥

7 0

4 years ago

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Your goal is to create a college fund for your child. Suppose you find a fund that offers an APR of 7 %. How much should you dep

Yanka [14]

Answer:

You shoud invest $0.204, it is an small amount each month.

The formula to calculate the monthly saving is

$PP= \frac{A(APR/n)}{(1+(APR/n))^{nY}-1}$