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vovikov84 [41]
3 years ago
6

Ann is preparing for the Valentine's Day dance. She is cutting out 476 hearts a day. If she cuts out hearts for 18 days, how man

y hearts will she cut in all

Mathematics
1 answer:
allsm [11]3 years ago
7 0

Answer:

8568 paper hearts were cut in the making of this process :DDDDDDDDDDDDDDDDDDDDDDDDD

Step-by-step explanation:

18 times 400 = 7200

18 times 70 = 1260

18 times 6 = 108

3200+560+48= 8568

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For the equation, determine whether the equation is true for all, some, or no values of x.
vichka [17]

Answer:

nothing can be further done with this topic. please check the expression entered or submit a picture for futher understanding

Step-by-step explanation:

8 0
2 years ago
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Emily and Kate were at a cheerleading competition this fall.They cheered 12 rounds. Each round lasted 8.24 minutes. Calculate th
trapecia [35]

Answer:

98.88

Step-by-step explanation:

Given: They cheered 12 rounds. Each round = 8.24

To find the total number, multiply how much one round is with the total number of rounds.

  8.24

×     12

-----------

  1648

+ 8240

----------

98.88

Each girl cheered 98.88 minutes. If you need this estimated, the answer would be 99 minutes.

4 0
2 years ago
Mr. Sonny's science class is calculating the average number of blinks per minute. Jan blinks 126 times in 7 minutes. What is her
vlabodo [156]
18 blinks per min since 126 divided by 7 equals 18
3 0
2 years ago
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Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0
\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0

which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
the crowd at a sporting event is estimated to be 2,500 people. the exact attendance is 2,486 people. what is the percentage erro
Verdich [7]

Answer:

0.56%

Step-by-step explanation:

Percentage error

=  \frac{2500 - 2486}{2500}  \times 100 \\  \\  =  \frac{1400}{2500}  \\  \\  = 0.56\%

5 0
3 years ago
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