Solve for x. x+2/3=−1/6 Please help I'll give brainliest
1 answer:
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Answer:
f(2) = 36
Step-by-step explanation:
given f(x) =
To evaluate f(2) substitute x = 2 into f(x)
f(2) = 6² = 6 × 6 = 36
Answer:
C
Step-by-step explanation:
The zeros of the function is the roots and solutions. To find them, factor the equation into two binomials.
To solve, set each binomial to 0 and solve for x.
x+6 = 0
x = -6
x-5=0
x=5
Answer:
(a) The 29th percentile for the number of chocolate chips in a bag is 1198.65.
(b) The number of chocolate chips in a bag that make up the middle 95% of bags are [1146, 1380].
(c) The inter-quartile range of the number of chocolate chips in a bag of chocolate chip cookies is 157.83.
Step-by-step explanation:
Let the random variable <em>X</em> represent the number of chocolate chips in a bag of chocolate chip cookies.
The random variable <em>X</em> is normally distributed with mean, <em>μ </em>= 1263 and a standard deviation, <em>σ </em>= 117.
(a)
Compute the 29th percentile for the number of chocolate chips in a bag as follows:
P (X < x) = 0.29
⇒ P (Z < z) = 0.29
The value of <em>z</em> for the above probability is, <em>z</em> = -0.55.
Compute the value of <em>x</em> as follows:
Thus, the 29th percentile for the number of chocolate chips in a bag is 1198.65.
(b)
According to the Empirical rule 95% of the normally distributed data lies within 2 standard deviations of the mean.
P (μ - σ < X < μ + σ) = 0.95
P (1263 - 117 < X < 1263 + 117) = 0.95
P (1146 < X < 1380) = 0.95
Thus, the number of chocolate chips in a bag that make up the middle 95% of bags are [1146, 1380].
(c)
The inter-quartile range of the normal distribution is:
IQR = 1.349 <em>σ</em>
Compute the inter-quartile range of the number of chocolate chips in a bag of chocolate chip cookies as follows:
IQR = 1.349 <em>σ</em>
= 1.349 × 117
= 157.833
Thus, the inter-quartile range of the number of chocolate chips in a bag of chocolate chip cookies is 157.83.