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BabaBlast [244]
4 years ago
13

Is 67 a multiple of 5

Mathematics
2 answers:
tankabanditka [31]4 years ago
3 0
No, because all multiples of 5 end with 5 or 0
andrezito [222]4 years ago
3 0
No, 67 is not a multiply of 5. 

no number times 5 will equal 67. 
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Factorization of 3x2-8x-3
pychu [463]
<span>3x</span>² <span>- 8x -3  = 3x</span>² - 9x + x - 3 =

= 3x² - 9x + x - 3 = 3x* ( x - 3) + 1* (x - 3) = 

= 3x * (x - 3) + 1 * (x - 3) = (3x + 1) (x - 3) 

Answer (3x + 1) (x - 3)

3 0
3 years ago
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Please help I've been trying to figure it out but I can't​
Savatey [412]

answer : 2 1/2

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6 0
2 years ago
We have a jar of coins, all pennies and dimes. All together, we have 309 coins, and the total value of all coins in the jar is $
Vinvika [58]

There are 130 pennies in the jar

Step-by-step explanation:

We have a jar of coins

  • All coins are pennies and dimes
  • There are 309 coins in the jar
  • The total value of all coins in the jar is $ 19.2

We need to find the number of pennies in the jar

Assume that there are p pennies and d dimes in the jar

∵ There are p pennies and d dimes in the jar

∵ There are 309 coins in the jar

∵ All the coins in the jar are pennies and dimes

∴ p + d = 309 ⇒ (1)

∵ The total value of all coins in the jar is $ 19.2

∵ $1 = 100 cents

∴ $19.2 = 19.2 × 100 = 1920 cents

∵ 1 penny = 1 cent

∵ 1 dime = 10 cents

∴ p + 10 d = 1920 ⇒ (2)

Now we have system of equations, we can solve them to find p

∵ p + d = 309 ⇒ (1)

∵ p + 10 d = 1920 ⇒ (2)

- Multiply equation (1) by -10 to eliminate d

∵ (-10)(p) + (-10)(d) = (-10)(309)

∴ -10 p - 10 d = -3090 ⇒ (3)

Add equations (2) , (3)

∴ -9 p = -1170

- Divide both sides by -9

∴ p = 130

There are 130 pennies in the jar

Learn more:

You can learn more about the system of equations in brainly.com/question/3739260

#LearnwithBrainly

8 0
3 years ago
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strojnjashka [21]
Equation because then you need to divide and multiply
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Do these ratios form a proportion? 26 medium hats to 2 small hats 39 medium hats to 3 small hats
inessss [21]

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7 0
3 years ago
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