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Aneli [31]
3 years ago
15

IF YOU SOLVE I WILL BE YOUR BEST FRIEND I SWEAR. ALSO WILL AWARD THE BRAINLIEST THING. PLEASE. I NEED THESE GRADES SO I WONT BE

A DISSAPOINTMENT TO MY MY MOM!

Mathematics
1 answer:
asambeis [7]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

x⁵ - 8x⁴ + 22x³ - 26x² + 21x - 18 = 0

x = 2,  x = ± i,   x=3  with multiplicity 2

-----------------------------------------------------

x⁴ - 5x³ + 7x² - 5x + 6 = 0

x = 2,   x=3,   x = ± i

--------------------------------------------------------

<u>-1 + 4i</u>    =  4 + i

    i

--------------------------------------------------------

x³ - 26x² + 21x - 18 = 0

x = ± 2i,   x = 3/2

--------------------------------------------------------

(1 + i) (-3 - 4i)

= 1 - 7i

--------------------------------------------------------

6.

(-5 + 2i) + (3 - 6i)

= -2 -4i

--------------------------------------------------------

7.

x⁴ + 5x² + 4 = 0

x = ± i ,     x = ± 2i

--------------------------------------------------------

8.

(7 - i) - (-5 + 6i)

= 12 - 7i

--------------------------------------------------------

9.

(4 - i) (4 + i)

= 17

--------------------------------------------------------

10.

(3 + 8i) (4 - 3i)

= 36 + 23i

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4 0
3 years ago
Krista's mom has told her she needs to make the pen ½ the size that she had planned (5 feet long by 4 ½ feet wide). What will th
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Answer:

1. area of new pen = 11 \frac{1}{4} ft^{2}

2. i. 5 feet by 2\frac{1}{4} feet

ii. 2 ½ feet by 4 ½ feet

Step-by-step explanation:

The size of the pen as planned = 5 ft long by 4 ½ ft wide

Area of the pen = length x width

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Area of the pen = \frac{45}{2}

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But, Krista has to make the pen ½ the size of planned. So that;

area of new pen = ½ x 22 ½

        = ½ x \frac{45}{2}

        = \frac{45}{4}

        = 11 \frac{1}{4}

area of new pen = 11 \frac{1}{4} ft^{2}

The area of the new pen would be 11 \frac{1}{4} ft^{2}.

The possible values she could use are:

i. 5 feet by 2\frac{1}{4} feet

ii. 2 ½ feet by 4 ½ feet

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