Answer
A. The median for town A, 20, is less than the median for town B, 30°
Step-by-step Explanation:
The median of town A and town B, as can be observed from box plots in the diagram attached below, can be gotten by locating the data points where the line divides the box into 2.
For town A, the data point at which a line divides the box is at 20⁰, while for town B, the data point at which the line divides the box is at 30⁰.
Median for town A is 20⁰, while median for town B is 30⁰. Therefore, the statement that most appropriately compare the centers is A. "The median for town A, 20, is less than the median for town B, 30°".
Answer:
The answer is "0.7794".
Step-by-step explanation:
Please find the complete question in the attached file.
Given:
Hypotheses:
Testing statistics:
The test is done just so the p-value of a test is
Because the p-value of the management is large, type B can take it.
Bill's speed is constant after 5 seconds and 45 meters into the race.
Correct responses:
a. Bill's maximum speed is 8 m/s
b. 24 meters
c. 57 meters
<h3>Methods used to calculate speed and distance traveled</h3>Given parameters are;
The distance of the race = 100 meter
Distance at which Bill reaches maximum speed = 45 meters
Speed Bill maintains after 5 seconds = The maximum speed
Time at which Bill is 85 meters from the starting line = 10 seconds after start
a. Required;
Bill's maximum speed in meters.
Solution:
Distance Bill runs at maximum speed, d = 85 m - 45 m = 40 m
Time at which Bill runs the 40 m at maximum speed, <em>t</em> = 10 s - 5 s = 5 s
Therefore;
b. i. Required:
The distance Bill will run for 3 seconds at the maximum speed;
Solution:
Distance,<em> s</em> = Speed, <em>v</em> × Time, <em>t</em>
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The distance traveled at maximum speed in 3 seconds is therefore;
Distance = 8 m/s × 3 s = 24 m
The distance Bill travels in 3 seconds at the maximum speed is 24 meters.
ii) The distance Bill travels at 8 seconds after start, is given as follows;
Distance traveled in the first 5 seconds = 45 meters
Distance traveled in the next 3 seconds = 24 meters
Therefore;
c. Bill's distance 6.5 seconds after the start of the race is given as follows;
Distance traveled in the first 5 seconds = 45 meters
Distance traveled in the next 1.5 seconds = 1.5 s × 8 m/s = 12 meters
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