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Fudgin [204]
3 years ago
9

Juan has 40 pieces of paper and it has seven times as many pieces of paper as Juan​

Mathematics
2 answers:
castortr0y [4]3 years ago
6 0

Answer:

280

Step-by-step explanation:

Annette [7]3 years ago
5 0
I think it is 40 x 7 = 280
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Which statement below shows the best use of friendly numbers to estimate the value of 27 x 4
topjm [15]
27x4=108 is the best form and answer



3 0
3 years ago
Read 2 more answers
A random sample of 12 chemists from Washington stats shows an average salary of $39,420 with a standard deviation of $1659. A ra
cestrela7 [59]

Answer:

Step-by-step explanation:

Given that :

μ1 = 39420 ; σ1 = 1659 ; s1 = 12

μ2 = 30215 ; σ2 = 4116 ; s2 = 26

df1 = 12 - 1 = 11

df2 = 26 - 1 = 25

98 % confidence interval of the difference in sample means :

Pooled Variance :

S²p = ((df1 * s1²) + (df2 * s2²)) / (df1 + df2)

((11×1659^2)+(25×4116^2))÷(11+25) = 12605874.75

Standard Error :

√(S²p/n1) + (S²p/n2)

√(12605874.75/12) + (12605874.75/26)

= 1239.0847

8 0
3 years ago
I NEED HELP!! ITS IMPORTANT
Rudiy27

Answer:

2/10 .02

Step-by-step explanation:

7 0
3 years ago
Find the value of x<br><br> Can u please explain
Vlad1618 [11]

Answer:

can u please tell what is 158° here

8 0
2 years ago
Read 2 more answers
Please help me answer one of these!
babunello [35]

This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.


There aren't any parallel lines involved in the above described construction, so I'll skip the first one.


2. Why do the circles have to be congruent ...


The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.


3. ... circles of different sizes ...


[We just answered that. Let's do it again.]


Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.


4. ... construct the perpendicular bisector ... a different way?


Maybe what I first described is different; there are no parallel lines.



8 0
4 years ago
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