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Dmitrij [34]
3 years ago
11

A researcher brings a sample of dry soil to the lab, wets it, provides ample amounts of fertilizer, and places the soil in a con

tainer in a greenhouse. Which type of plant would be least likely to emerge?
Biology
1 answer:
Kobotan [32]3 years ago
7 0

OPTIONS:

A. Pine seedling B. Sunflower C. Corn D. Wheat E. Liverwort

Answer:

E. Liverwort

Explanation:

Liverworts are non-vascular plants that reproduce by producing spores. Liverworts are mostly found in damp and moist areas where they emerge better.

Among the options given, Liverwort is the least likely to emerge simply because of the nature or characteristics of Liverworts that make them prefer damp or moist environment to thrive better. A a result of lack of vascular tissues in Liverwort, which is important for plants to carry and store water throughout the plants, a continuous absorption of water is needed for the Liverwort to thrive since it is poor in transporting and storing water, unlike the other plants listed .

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3 years ago
You are studying a population of snapdragon plants on Membata Island. In snapdragons, the dominant allele CR encodes red flowers
fredd [130]

Answer:

we will know that the allelic frequencies are for R 0.95 and r 0.05

Explanation:

We know that the population is in Hardy-Winberg equilibrium, we deduce the following formula:

p + q = 1

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data

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p would be equal to the allelic frequency R

q will be equal to the frequency allelic r

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2pq = Rr

If there are 25 white flowers in 1000 plants, their frequency will be:

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we deduce that q is equal to 0.05

we replace the data with the previous formula

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p = 1-0.05

we get as a result

  p = 0.95

if p = 0.95 and q = 0.05

we will know that the allelic frequencies are for R 0.95 and r 0.05

7 0
3 years ago
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prohojiy [21]
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Explanation:

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