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solong [7]
3 years ago
7

I am finding the mean of 13, 14 , 0, 36, 18 ,12. I got an answer of 15r3 how is the answer 15.5 and not 15.3

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
5 0
Mean = 13 + 14 + 0 + 36 + 18 + 12 / 6
Mean = 93/6
Mean = 15.5

So, yeah answer would be 15.5
Karolina [17]3 years ago
3 0
13+14+0+36+18+12=6 \\ 93=6x \\ x=15.5

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Please please help me!!
makvit [3.9K]

Answer:

f(x)= - l x - (-4) l + 0

Step-by-step explanation:

6 0
3 years ago
Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4
vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

c^2 = 4^2 + 6^2

c^2 = 16 + 36

c^{2} = 52

Pythagoras' theorem for the middle one :

b^{2} = 6^{2} + a^{2}

Pythagoras' theorem for the biggest one :

(4+a)^2 = c^2 + b^2

16 + 8a + a^2 = 52 + b^2

Using the formula before (for b^2) it becomes :

16 + 8a + a^2 = 52 + (6^2 + a^2)

16 + 8a + a^2 = 52 + 6^2 + a^2

16 + 8a = 52 + 6^2

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

a = \frac{72}{8}

a = 9

Verifying :

b^2 = 6^2 + a^2

b^2 = 36 + 81

b^2 = 117

b^{2} = 117

The biggest one :

(4+a)^2 = c^2 + b^2

(4+9)^2 = 52 + 117

13^2 = 169

True

8 0
3 years ago
I WILL GIVE U BRAINLIEST AND THANKS AND 5 STARS
Effectus [21]

Answer:

I agree with Noah's Method because following PEMDAS you have to do exponents first. 10^3 is 1000 and then you can add the 20. Jada's method is incorrect because you cannot add the two together.

6 0
3 years ago
What number is not part of the domain of f(x)= 3/ x+5<br> (3 over x + 5)
nignag [31]
-5, you never want the denominator to equal zero or else it doesnt exist!

x+5=0
x=-5
7 0
3 years ago
PLEASE HELP!! NO LINKS!! GIVING 20 POINTS AWAY!!
shutvik [7]

Answer:

m\angle N = 32\degree

m\widehat {NQ}=106\degree

Step-by-step explanation:

By inscribed angle theorem:

m\angle N = \frac{1}{2} \times m\widehat {MP}

m\angle N = \frac{1}{2} \times 64\degree

m\angle N = 32\degree

Again by inscribed angle theorem:

m\angle P= \frac{1}{2} \times m\widehat {NQ}

53\degree = \frac{1}{2} \times m\widehat {NQ}

2\times 53\degree = m\widehat {NQ}

m\widehat {NQ}=106\degree

5 0
3 years ago
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