Respuesta: x/2,5=y/5=4/5=0,8
x/2,5=y/5
Multiplicando ambos lados de la ecuación por 5:
5(x/2,5)=5(y/5)→2x=y→y=2x
Sustituyendo y por 2x en la ecuación x+y=6:
x+2x=6
Resolviendo para x: Sumando términos semejantes:
3x=6
Dividiendo ambos lados de la ecuación entre 3:
3x/3=6/3
x=2
Sustituyendo x por 2 en la formula y=2x
y=2(2)→y=4
Determinando la proporción:
x/2,5. Sustituyendo x por 2:
2/2,5
Multiplicando numerador y denominador por 2:
2*2/(2,5*2)=4/5
La proporción es 4/5=0,8
Si lo hacemos con y:
y/5
Reemplazando y por 4:
4/5=0,8 (la misma proporción)
Answer:
585$
Step-by-step explanation:
25% of 450$ is 112.5
5% is 22.5
add all of this to the 450 and you get the answer!
Answer: The total number of logs in the pile is 6.
Step-by-step explanation: Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two logs.
We are to find the total number of logs in the pile.
Let n represents the total number of logs in the pile.
Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with
first term, a = 32 and common difference, d = -6.
We know that
the n-th term of an arithmetic sequence with first term a and common difference d is

Since there are n logs in the pile, so we get

Thus, the total number of logs in the pile is 6.
Answer:
C. True; by the Invertible Matrix Theorem if the equation Ax=0 has only the trivial solution, then the matrix is invertible. Thus, A must also be row equivalent to the n x n identity matrix.
Step-by-step explanation:
The Invertible matrix Theorem is a Theorem which gives a list of equivalent conditions for an n X n matrix to have an inverse. For the sake of this question, we would look at only the conditions needed to answer the question.
- There is an n×n matrix C such that CA=
. - There is an n×n matrix D such that AD=
. - The equation Ax=0 has only the trivial solution x=0.
- A is row-equivalent to the n×n identity matrix
. - For each column vector b in
, the equation Ax=b has a unique solution. - The columns of A span
.
Therefore the statement:
If there is an n X n matrix D such that AD=I, then there is also an n X n matrix C such that CA = I is true by the conditions for invertibility of matrix:
- The equation Ax=0 has only the trivial solution x=0.
- A is row-equivalent to the n×n identity matrix
.
The correct option is C.