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RUDIKE [14]
4 years ago
7

Just 7 and 8 please!!

Mathematics
1 answer:
77julia77 [94]4 years ago
4 0
Just multiply it so multiply 59.89 x 4 and then for number 8 multiply 88.70 x 4
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Son proporciones.<br> cual es el resultado de :x/2,5=y/5 si x+y=6
omeli [17]

Respuesta: x/2,5=y/5=4/5=0,8


x/2,5=y/5

Multiplicando ambos lados de la ecuación por 5:

5(x/2,5)=5(y/5)→2x=y→y=2x

Sustituyendo y por 2x en la ecuación x+y=6:

x+2x=6

Resolviendo para x: Sumando términos semejantes:

3x=6

Dividiendo ambos lados de la ecuación entre 3:

3x/3=6/3

x=2

Sustituyendo x por 2 en la formula y=2x

y=2(2)→y=4

Determinando la proporción:

x/2,5. Sustituyendo x por 2:

2/2,5

Multiplicando numerador y denominador por 2:

2*2/(2,5*2)=4/5

La proporción es 4/5=0,8

Si lo hacemos con y:

y/5

Reemplazando y por 4:

4/5=0,8 (la misma proporción)


7 0
3 years ago
What is the domain of f(x) = sqrt(x^2 - 4)
wolverine [178]
I think c      skrrr pop pop
6 0
3 years ago
A student is raising money for cancer research. A local business agrees to donate an additional 25% of what the student raises,
Galina-37 [17]

Answer:

585$

Step-by-step explanation:

25% of 450$ is 112.5

5% is 22.5

add all of this to the 450 and you get the answer!

7 0
4 years ago
Read 2 more answers
A stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer. If the top laye
Svetlanka [38]

Answer:  The total number of logs in the pile is 6.

Step-by-step explanation:  Given that a stack of logs has 32 logs on the bottom layer. Each subsequent layer has 6 fewer logs than the previous layer and the top layer has two​ logs.

We are to find the total number of logs in the pile.

Let n represents the total number of logs in the pile.

Since each subsequent layer has 6 fewer logs then the previous layer, so the number of logs in each layer will become an ARITHMETIC sequence with

first term, a = 32  and  common difference, d = -6.

We know that

the n-th term of an arithmetic sequence with first term a and common difference d is

a_n=a+(n-10)d.

Since there are n logs in the pile, so we get

a+(n-1)d=2\\\\\Rightarrow 32+(n-1)(-6)=2\\\\\Rightarrow 32-6n+6=2\\\\\Rightarrow 6n=36\\\\\Rightarrow n=6.

Thus, the total number of logs in the pile is 6.

6 0
3 years ago
For this exercise assume that all matrices are ntimesn. Each part of this exercise is an implication of the form​ "If "statement
inna [77]

Answer:

C. True; by the Invertible Matrix Theorem if the equation Ax=0 has only the trivial solution, then the matrix is invertible. Thus, A must also be row equivalent to the n x n identity matrix.

Step-by-step explanation:

The Invertible matrix Theorem is a Theorem which gives a list of equivalent conditions for an n X n matrix to have an inverse. For the sake of this question, we would look at only the conditions needed to answer the question.

  • There is an n×n matrix C such that CA=I_n.
  • There is an n×n matrix D such that AD=I_n.
  • The equation Ax=0 has only the trivial solution x=0.
  • A is row-equivalent to the n×n identity matrix I_n.
  • For each column vector b in R^n, the equation Ax=b has a unique solution.
  • The columns of A span R^n.

Therefore the statement:

If there is an n X n matrix D such that AD=​I, then there is also an n X n matrix C such that CA = I is true by the conditions for invertibility of matrix:

  • The equation Ax=0 has only the trivial solution x=0.
  • A is row-equivalent to the n×n identity matrix I_n.

The correct option is C.

5 0
4 years ago
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