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MrMuchimi
3 years ago
13

In the formula, v=L(1-

Mathematics
1 answer:
wolverine [178]3 years ago
3 0
The value of the the car is given by:
V=L(1-d.n)
thus, the value of v when L=$21000 and d.n=0.7 will be:
V=21000(1-0.7)
V=21000×0.3
V=$6300

Answer: Present value of the car is $6300
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The angle measurements in the diagram are represented by the following expressions​
KIM [24]

Answer:

x = 12

∠A = 144

Step-by-step explanation:

+ We have: ∠A = ∠C (alternate interior)

                ∠D = ∠C ( vertically opposite angles)

=> ∠A = ∠C (because = ∠C)

=> 10x + 24 = 6x + 72

=> 10x - 6x = 72 - 24

        4x      = 48

          x      = 12

+ ∠A = 10x + 24

 ∠A = 10 x 12 + 24

∠A = 144

7 0
3 years ago
I need to know how to do this 14+(64/8)-11
amm1812
The answer is 11

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Resolver el siguiente sistema de ecuación:
snow_tiger [21]

Answer:

x=-1\\y=4

Step-by-step explanation:

\frac{5x+2y}{3}=1

\frac{2x+y}{2}=1

Vamos a utilizar el método de sustitución. Vamos a despejar la segunda ecuación por alguna de las variables. Elegiré la y porque esta sola.

\frac{2x+y}{2}=1

Vamos a empezar por eliminar ese 2 del denominador. Para hacer esto, multiplicamos por 2 ambos lados de la ecuación.

2x+y=1*2

2x+y=2

Como vamos a despejar la y, restamos 2x en ambos lados.

y=2-2x

Listo.

------------------------------------------------------------------------

Procedemos a reemplazar el valor de y en la primera ecuación.

\frac{5x+2y}{3}=1

\frac{5x+2(2-2x)}{3}=1

\frac{5x+4-4x}{3} =1

Procedemos a operar términos semejantes.

\frac{x+4}{3} =1

Nos deshacemos del 3 multiplicando.

x+4=1*3\\x+4=3

Restamos 4

x=3-4\\x=-1

-----------------------------------------------------------------------------

Una vez encontrado el valor de x, procedemos a reemplazar en cualquier ecuación para encontrar el valor de y. Usaré la segunda ecuación.

\frac{2x+y}{2}=1

\frac{2(-1)+y}{2}=1

Procedemos a resolver;

\frac{-2+y}{2} =1

Multiplicamos por 2.

-2+y=1*2

-2+y=2

Sumamos 2

y=2+2\\y=4

-------------------------------------------------------------------------------

Para comprobar que los valores son correctos, reemplazamos ambos valores en cualquier ecuación y el resultado debe ser igual.

Usaré la primera.

\frac{5x+2y}{3} =1

\frac{5(-1)+2(4)}{3} =1

Resolvemos;

\frac{-5+8}{3} =1

\frac{3}{3}=1

1=1

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