The answer is D
Type 1 Type 2 plants have somewhat similar height distributions
Answer:
15. 50 kg
16a. 5 kg
16b. 3.75 kg
Step-by-step explanation:
The formula relating force, mass, and acceleration can be solved for mass. This formula will apply to both problems. We'll use m for both "mass" and "meters". We presume you can avoid getting mixed up by understanding that meters is used in the context of acceleration: m/s².
F = ma
m = F/a . . . . . divide by a
__
15. m = (250 N)/(5 m/s²) = 50 kg
__
16a. m = (15 N)/(3 m/s²) = 5 kg
16b. m = (15 N)/(4 m/s²) = 3.75 kg
_____
<em>Comment on units</em>
Especially for physics problems, I like to keep the units with the numbers. It is helpful to remember that Newtons are equivalent to kg·m/s². So, dividing Newtons by acceleration in m/s² will give mass in kg. Since you're familiar with F=ma, it's not too hard to remember that the units of force (N) are the product of the units of mass (kg) and acceleration (m/s²).
The answer to your problem is
0.57735026919
-2 + 3b = 5b - 2(2b + 3) Distribute the -2 through the parentheses.
-2 + 3b = 5b - 4b - 6 Combine like terms
-2 + 3b = b - 6 Bring all "b's" to one side of the equation
-2 + 3b - b = b - b - 6 Combine like terms
-2 + 2b = -6 Bring the 2 to the right side of the equation
-2 + 2 + 2b = -6 + 2 Combine like terms
2b = -4 Isolate b by dividing both sides by 2
b = -4/2 = -2
Answer b = -2
81 is 45% of 180.
Simply multiply the percentage rate to the whole to get the part it is representing.
180 is the whole or 100%
45% is the percentage rate of the part.
180 x 45% = 81
81 is the value of the part
Assuming the part and the whole is given, to get the percentage rate, simply divide the part by the whole. and multiply its quotient by 100%.
81/180 = 0.45 x 100% = 45%
In the instance that the part and its corresponding percentage rate is given, find the whole. divide the part by its percentage rate.
81/45% or 81/0.45 = 180
