Solve: 5a + 15 = 45 O a = 12 O a = 6 O a = -6 O a = -12

Sindrei [870]

The answer is: [C]: " 3 " .
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Explanation:
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4x - 1 = 2x + 5 ; Solve for "x" ;
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Subtract "2x" from each side of the equation; and add "1" to each side of the equation:
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4x - 1 - 2x + 1 = 2x + 5 - 2x + 1 ;
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2x = 6 ;
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Divide EACH side of the equation by "2" ; to isolate "x" on ONE side of the equation; and to solve for "x" ;
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2x / 2 = 6 / 2 ;
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x = 3 .
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The answer is: [C]: " 3 " .
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4 0

3 years ago

What is interest earned on 3500 invested at 6% compounded quarterly or 12 years

enyata [817]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$3500\\
r=rate\to 6\%\to \frac{6}{100}\to &0.06\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{quarterly, thus four}
\end{array}\to &4\\
t=years\to &12
\end{cases}
\\\\\\
A=3500\left(1+\frac{0.06}{4}\right)^{4\cdot 12}\implies A=3500(1.015)^{48}$

so, the interest earned then will be A - 3500.

6 0

3 years ago

What is radians converted to degrees? If necessary, round your answer to the nearest degree.

Tomtit [17]

To convert radians to degrees, make use of the fact that pi radians equals one half circle, or 180º.

This means that if you divide radians by pi, the answer is the number of half circles. Multiplying this by 180º will tell you the answer in degrees.

So, to convert radians to degrees, multiply by 180/pi, like this:

Degrees= radians X 180/pi

3 0

3 years ago

A peregrine falcon can fly 322 kilometers per hour.how many meters per hour can the falcon fly

vivado [14]

The falcon can fly 322,000 meters per hour.

1 kilometer is 1000 meters, meaning you would multiply 322 by 1000 equaling 322,000.

5 0

3 years ago

Suppose a certain home improvement outlet knows that the monthly demand for framing studs is 2,300 when the price is $4.77 each

pogonyaev

Answer:

p + 0.0001q = 5

Step-by-step explanation:

Data provided in the question:

When Price, p₁ = $4.77 ; Demand, q₁ = 2,300

and,

When Price, p₂ = 3,300 ; Demand, q₂ = 3,300

considering the above as the points on the line,

now, the general equation for a line is given as:

$\frac{q_1-q}{p_1-p}=\frac{q_2-q_1}{p_2-p_1}$

on substituting the respective values, we get

$\frac{2,300-q}{4.77-p}=\frac{3,300-2,300}{4.67-4.77}$

or

$\frac{2,300-q}{4.77-p}=\frac{1000}{-0.1}$

or

2,300 - q = -10,000(4.77 - p)

or

⇒ 2,300 - q = -47700 + 10,000p

or

⇒ 10,000p + q = 2300 + 47700

or

⇒ 10,000p + q = 50000

or

⇒ p + 0.0001q = 5

8 0

3 years ago