To solve this problem you must apply the procceddure shown below:
1. You have the following system of equations:
<span>
x+y = 3
2x–y = 6
2. Then, you must clear the variable y from the first equation and susbtitute it into the second equation, as below:
x+y=3
y=3-x
2x-y=6
2x-(3-x)=6
2x-3+x=6
3x=6+3
3x=9
3. Therefore, the value of x is:
x=9/3
x=3
4. As you can see, the correct answer is:
x=9
</span>
Answer:
d. 15
Step-by-step explanation:
Putting the values in the shift 2 function
X1 + X2 ≥ 15
where x1= 13, and x2=2
13+12≥ 15
15≥ 15
At least 15 workers must be assigned to the shift 2.
The LP model questions require that the constraints are satisfied.
The constraint for the shift 2 is that the number of workers must be equal or greater than 15
This can be solved using other constraint functions e.g
Putting X4= 0 in
X1 + X4 ≥ 12
gives
X1 ≥ 12
Now Putting the value X1 ≥ 12 in shift 2 constraint
X1 + X2 ≥ 15
12+ 2≥ 15
14 ≥ 15
this does not satisfy the condition so this is wrong.
Now from
X2 + X3 ≥ 16
Putting X3= 14
X2 + 14 ≥ 16
gives
X2 ≥ 2
Putting these in the shift 2
X1 + X2 ≥ 15
13+2 ≥ 15
15 ≥ 15
Which gives the same result as above.
Answer:
ez
Step-by-step explanation:
